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Gnom [1K]
3 years ago
13

For which intervals is the function increasing?

Mathematics
2 answers:
zzz [600]3 years ago
7 0
It is increasing at (−∞, 0) and (1, 2)
stiks02 [169]3 years ago
6 0

Answer:

The intervals where the function is increasing are (-\infty,0) and (1,2)

Step-by-step explanation:

We are required to find the intervals in which the function is increasing.

From the figure, we see that,

The graph is going up towards the origin to reach the point (0,0).

Then, it is going down in the interval (0,1).

Then, it is again going up to reach the point (2,0).

Finally, it is going downwards towards infinity.

Thus, we see that,

The intervals where the function is increasing are (-\infty,0) and (1,2)

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A rectangle with vertices (3,-2),(3,-4), (7, -2), (7, -4) is reflected across the x-axis and then rotated 90° counterclockwise.
BigorU [14]

Answer: A reflection about the y-axis and a clockwise rotation of 90° around the origin.

another example is:

A counterclockwise rotation of 90° around the origin, and then a reflection about the y-axis.

Step-by-step explanation:

Let's do this for a single point because it is essentially the same.

Let's use the point (3, -2)

First, we have a reflection across the x-axis, this only changes the sign of the y-component.

Then the new point will be: (3, -(-2)) = (3, 2)

Notice that this point is on the first quadrant.

Now we do a 90° counterclockwise rotation.

Then we move to the second quadrant, and we change the order of the components in the point (and because we are in the second quadrant, the x-component is negative and the y-component is positive)

Then the new point is (-2, 3)

Now, another transformation that is equivalent to this one is to do first a reflection about the y-axis, so we only change the sign of the y-component

Then the new point is (-3, -2)

And now we are in the third quadrant.

and then we do a rotation of 90° clockwise, which moves our point to the second quadrant, changes the order of the components and leaves the y-component positive and the x-component negative, then the new point is:

(-2, 3)

Same as before.

(notice that we used the same transformations, but applied to different line and direction of rotation)

Another example is if we first start with a counterclockwise rotation of 90° around the origin, the original point (3, -2) is on the fourth quadrant, so this rotation leaves our point in the first quadrant, so we change the order of the components and both of them will have a positive sign.

The new point is: (2, 3)

Now let's do a reflection about the y-axis, which changes the sign of the x-component.

Then the final point is (-2, 3), same as before.

And there are a lot of other transformations that will be equivalent to this ones, these are just two examples.

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