Answer:
Compare the predictions in terms of the predictors that were used, the magnitude of the difference between the two predictions, and the advantages and disadvantages of the two methods.
Our predictions for the two models were very simmilar. A difference of $32.78 (less than 1% of the total price of the car) is statistically insignificant in this case. Our binned model returned a whole number while the full model returned a more “accurate” price, but ultimately it is a wash. Both models had comparable accuracy, but the full regression seemed to be better trained. If we wanted to use the binned model I would suggest creating smaller bin ranges to prevent underfitting the model. However, when considering the the overall accuracy range and the car sale market both models would be
Explanation:
Answer:Thank you very much! A user names SShalomeea has been hacking today. Anyone with that photo is a spammer.
Answer:
The answer is "DDoS
"
Explanation:
The distributed denial of service attack (DDoS) occurs whenever a directed program's wireless data or assets, generally one or even more application servers, were also swamped by various machines. This attack is always the consequence of many affected systems, that fill up the target network with traffic.
- This attack is aimed to avoid legal customers of one's website from accessing it.
- In being effective in a DDoS attack, further demands need to be sent to the hacker than even the victim's server could deal with.
- One other way to successfully attack is to send fake requests from the attacker.
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.81 times.