Ask question

Ask question

All categories

4 years ago

14

I need help with this question !!!

1 answer:

jolli1 [7]4 years ago

5 0

What do you need help with? it helps us to know the question!

You might be interested in

How many mL are there in 3,700 microliters?

rewona [7]

Answer:

3.7 mL

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

- 7 and 8<br> What’s the answer

kvv77 [185]

Answer:

1

Step-by-step explanation:

8-7= 1

Hope this helps!

3 0

3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id

taurus [48]

Answer:

$\boxed{\bf \: \cfrac{13}{5}}$

<u>Or in Decimal:</u>

$\boxed{\bf \: 2.6}$

Step-by-step explanation:

<u>Given expression :-</u>

$\sf \: ( 26 \div 100) \times 10$

<u>Solution :-</u>

$\sf = (26 \div 100 )\times 10$

This arithmetic expression may be rewritten as ;

$\sf = \cfrac{26}{100} \times 10$

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

$\sf = \cfrac{26}{10 \cancel0} \times 1 \cancel0$

<em>Results to;</em>

$\sf = \: \cfrac{26}{10} \times 1$

$\sf = \: \cfrac{26}{10}$

Step 2: <u>Cancel 26 and 10</u><u> </u><u>by 2</u> :-

$\sf = \cfrac{ \cancel{26}}{ \cancel{10}}$

<em>Results to;</em>

$\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }$

$\sf = \cfrac{13}{5}$

<em>It can also be in Decimal.</em>

That is;

$\sf = 2.6$

Hence, the answer of the expression would be 13/5 or 2.6 .

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

3 0

3 years ago

Read 2 more answers

QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is

soldi70 [24.7K]

Answer:

$PQR = 20$

Step-by-step explanation:

Given

Bisector: QS

$PQS = 5x$

$RQS = 2x + 6$

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

$PQS = RQS$

Substitute expressions for PQS and RQS

$5x = 2x + 6$

Collect Like Terms

$5x - 2x = 6$

$3x = 6$

Divide both sides by 3

$x = 2$

Solving for PQR;

$PQR = PQS + RQS$

$PQR = 5x + 2x + 6$

$PQR = 7x + 6$

Substitute 2 for x

$PQR = 7 * 2 + 6$

$PQR = 14 + 6$

$PQR = 20$

4 0

4 years ago