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prohojiy [21]
3 years ago
14

If the x and y values in each pair of a set of ordered pairs are interchanged the resulting set of ordered pairs is known as the

Mathematics
1 answer:
pochemuha3 years ago
4 0

Answer:

Inverse of a relation

Reasoning:

the inverse of a function is a full function, this is just a set of pairs.  A set of pairs, or relation, where x and y values interchange are inverse of the relation.  A one to one function is when a function's inverse is also a function (doesn't have more than one y for each x) which can be tested for on the normal function's graph with a HORIZONTAL line test.  A normal parabola isn't one to one.  An onto function has to do with every value being used (I don't remember much about them, but once again this isn't a function, but rather a specific set of pairs/data)

Example of inverse of a relation:

Relation: {(0,5), (3,2)}

Inverse: {(5,0), (2,3)}

Example of inverse of a function:

f(x)=5x

f-1(x)=x/5

Example of a one to one function:

f(x)=x+1

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Find the limit............​
liubo4ka [24]

Answer: -\frac{9}{x^2}

====================================================

Work Shown:

\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9}{x+\Delta x} - \frac{9}{x}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x}{x(x+\Delta x)} - \frac{9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x-9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{9x-9x-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\

\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9}{x(x+\Delta x)}\\\\\\\displaystyle \frac{-9}{x(x+0)}\\\\\\\displaystyle -\frac{9}{x^2}\\\\\\

The trick here is to first simplify the expression so that the \Delta x term in the very lower denominator cancels out. This is to avoid dividing by zero. Once this division by zero error is avoided, we can replace the delta x term with 0 and evaluate the limit as \Delta x approaches 0 from the right or positive direction.

5 0
3 years ago
What value of x is in the solution set of -2(3x + 2) > -8x + 6?
n200080 [17]

Answer:

x > 5

Step-by-step explanation:

Given that:

= -2(3x + 2) > -8x + 6

 (negative sign before bracket will alter the internal signs when multiplied by each term)

= -6x - 4 > -8x +6

Taking x terms on left side and other constants on right side

= -6x + 8x > 6 +4

Signs will be changer for transferred terms

= 2x > 10

By Dividing both sides 2 we get

=x > 10/2

= x >5

5 0
3 years ago
Find the zeros of the quadratic function<br> f(x) = 2x2 - 6x – 8 from the graph.
S_A_V [24]

Answer: 2 and -8

Step-by-step explanation:

3 0
3 years ago
Compare (-18) + (-15) -23 ____15-18+23
lesya [120]

Alright here we go...

<u>(-18) + (-15) - 23</u>

-33 - 23

= -56

<u>15-18+23</u>

-3 + 23

= 20

so I don't know how you want me to compare it but,

(-18) + (-15) - 23 < 15-18+23

6 0
3 years ago
Tracy took a test that had 24 questions. She got 5/6 of the questions correct. How many questions did she answer correctly?
grandymaker [24]

Answer:

20

Step-by-step explanation:

so 5 out of 6

6 divides 24 equally in two parts

take one away every 6 questions

20 questions correctly

3 0
3 years ago
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