I am a two-digit number. The digits total is 13 when added together. The digit in the tens place is one less than the digit in t
2 answers:
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Answer:
x 19/6
Step-by-step explanation:
1. Multiply both sides by 6 (the LCM of 6,3)
5/2 + 3-x <= 2(x-2)
2. Simplify 5/2+3-x to 11/2-x
11/2 - x<=2 (x-2)
3. Expand.
11/2-x<= 2x-4
4. Add x to both sides.
11/2<= 2x-4+x
5. Simplify 2x-4+x to 3x-4.
11/2<=3x-4
6. Add 4 to both sides.
11/2+4<=3x
7. Simplify 11/2+4 to 19/2
19/2<=3x
8. Divide both sides by 3
19/2 /3 <=x
9. Simplify 19/2 /3 to 19/2*3
19/2*3<=x
10. Simplify 2*3 to 6
19/6<=x
11. Switch sides.
x>= 19/6
Hope this helps!