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Kruka [31]
3 years ago
10

I am a two-digit number. The digits total is 13 when added together. The digit in the tens place is one less than the digit in t

he ones place. What am I?
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0

The digit is 67.

If you appreciated my answer, please brainliest me!

tamaranim1 [39]3 years ago
4 0

Answer:

the answer is 67

Step-by-step explanation: because if you add 6 and 7 you get 13


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PLEASE HELP!!! GEOMETRY<br> please
Cloud [144]
Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85

4 0
3 years ago
What is the equation of the line that passes through the point (3,-3) and has a slope of 0?
Blizzard [7]

Answer:

given us,

slope= 0

(x1y1)= (3,-3)

here

(y-y1) =m(x-x1)

or, (y+3)=0(x-3)

or (y+3)= x-3

or, x+y= -3-3

x+y= -6

Step-by-step explanation:

x+y= -6

7 0
3 years ago
What is the domain of y=log(x+2)
Andru [333]

Answer:

\huge\boxed{x>-2\to x\in(-2;\ \infty)}

Step-by-step explanation:

y=\log(x+2)\\\\\bold{Domain:}\\\\x+2>0\qquad|\text{subtract 2 from both sides}\\\\x+2-2>0-2\\\\x>-2

8 0
3 years ago
100 points to answer!
choli [55]

Answer: 27.47

Step-by-step explanation:

(sin(70) * 10) / sin(20)) = 27.47

don't know much, but try that

4 0
3 years ago
Read 2 more answers
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
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