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Tresset [83]
3 years ago
12

Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line

Mathematics
1 answer:
mylen [45]3 years ago
4 0
A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t 
yr = 2 + 2 t 
zr = 6 + 2 t 

To represent the black ant, 
xb = t/2 
yb = 2 + 3 t 
zb = 2 + t 

To calculate,
at t = 0 
xb - xr = -3 
yb - yr - 2-2 = 0 
zb - zr = 2-6 = -4 
Therefore,
d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2 

If t = 2,
2 + 2*2 = 2 + 3*2
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PLEASE HELP!
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See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

\textrm{Slant height  l} = \sqrt{r^2 + h^2}  (1)

\textrm{Lateral surface area} = \pi r l

\textrm {Base area} = \pi r^2

\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l) (2)

\textrm{Volume V = } (1/3)  \pi r^2h (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA}  = 4\pi(4 + 8.944) =  4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04

Figure(b)

r = 7, h =15

\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55

\textrm{SA}  = 7\pi(7 + 16.55) =  517.89

Figure (c)

r = 5, l = 8

h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA}  = 5\pi(5 + 8) =  204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5


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2 years ago
Find a101 of the sequence 5,8,11,
guajiro [1.7K]

Answer:

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Step-by-step explanation:

This sequence es the sum of 3

5+3 =8

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then

101 = 100 + 1

the fisrt date is 5

the another 100:

100*3 = 300

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