Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line
1 answer:
A. The distance between the red ant and the black ant is five units.
To represent the red ant,
xr = 3 - t
yr = 2 + 2 t
zr = 6 + 2 t
To represent the black ant,
xb = t/2
yb = 2 + 3 t
zb = 2 + t
To calculate,
at t = 0
xb - xr = -3
yb - yr - 2-2 = 0
zb - zr = 2-6 = -4
Therefore,
d = √(9+16) = √(25) = 5
b. There will be no collision between the two ants.
To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2
If t = 2,
2 + 2*2 = 2 + 3*2
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Answer:
Step-by-step explanation:
Notice that:
● 1/2 = 0.5
● 4/5 = 0.8
0.8 is greater than 0.5.
So:
● 0.8 > 0.5
● 4/5 > 1/2
Answer:
A
Step-by-step explanation:
sin is opposite/hypotenuse, which is 24/26, simplifying to 12/13
1. 3h+11
2. -2r
3. g-4
4. 5f+4
5. 15z
From the last two facts, we get


Then

Answer:
b
Step-by-step explanation:
this means the graph rises.