Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
Answer:
angle 1 and angle 3 are congruent
Step-by-step explanation:
Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.
_____
If you like, you can get there algebraically:
m∠1 + m∠2 = 180
m∠3 + m∠2 = 180
Subtract the second equation from the first:
(m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)
m∠1 -m∠3 = 0 . . . . simplify
m∠1 = m∠3 . . . . . . add m∠3
When angle measures are the same, the angles are congruent.
∠1 ≅ ∠3
Answer:
22,950
Step-by-step explanation:
subtract 51,550 and 28,600. 0 - 0 = 0 then 5-0=5 5-6 you can not do so you barrow from the 1. 1 becomes 0 and 5 becomes 15. 15-6=9. 0-8 you can not do so you need to borrow from the 5. 5 becomes 4 and 0 becomes 10. 10-8=2. Finally, 4-2=2. Put is all together and you have 22,950.
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer: 90 per each is you want how much money is needed in total that is 47.20 dollars
Step-by-step explanation: