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Mila [183]
3 years ago
6

A man drove 5 miles directly east from his home, made a left turn at an intersection, and then traveled 11 miles duc north to hi

s place of work. If a road was made directly from his home to his place of work, what would its distance be?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0
Answer: About 12.083



Explanation:
In order to solve this you would use Pythagorean theorem.

You are given the length of the two legs (5 and 11)

So by plugging in 5 and 11 into A Squared plus B Squared = C Squared, you get that C^2= 146.

By finding the square root of both sides you get square root of 146, which is approximately 12.803

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C because you have to multiply the four measures together.
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How do you write 4 out of 20 into a decimal
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2x+7 is on the outside and 2x^4+21x^3+35x^2-37x+46 is inside the division sign. please help!! ...?
MrRissso [65]
We carry out long division:

First, we multiply 2x + 7 by x³ to obtain 2x⁴ + 7x³ and subtract this from the original to get the remainder:
14x³ + 35x² - 37x + 46
Now, we repeat this process and keep the numbers we multiply by and then add them in the end:
Multiply by 7x², remainder:
28x² - 37x + 46
Multiply by 14x, remainder:
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Multiply by -67.5, remainder:
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The answer is x³ + 7x² + 14x - 67.5 with a remainder of 326.5
6 0
3 years ago
22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p
Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

S_{n+1}=1.05*S_n+1000\\\\S_0=50000

(b) The salary 25 years after 2017 will be $217044.85.

(c) S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

Step-by-step explanation:

We can define the next year salary S_{n+1} as

S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)

Extending to 3 years (n+3)

S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)

Extending to 4 years (n+4)

S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)

We can now express a general equation for S_n (salary at n years from 2017)

S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

The salary at 25 years from 2017 (n=25) will be

S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85

8 0
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Serggg [28]

Answer:

3:5

Step-by-step explanation:

12:20 simplified:

They can both be divided by 4. That is the biggest number.

3:5

7 0
3 years ago
Read 2 more answers
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