The value of the derivative of functions h'(6) as requested in the task content is; 55.
<h3>What is the value of h'(6)?</h3>
Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.
Hence, the derivative of h(x) can be evaluated as;
h'(x)=4f'(x)+5g'(x)
On this note, by substitution, it follows that;
h'(6)=4(5)+5(7)
h'(6) = 55.
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Answer:
I'm glad you asked!
Step-by-step explanation:
So let's do it step by step.
Already she has to pay $
for going in.
She has 
whole pounds.
x 
or 
Add $ and $ 
.
Now let's do $1.25 divided by 10.
$ divided by $
Now let's do 
times 
x 
Now let's add 7.5 to 0.5
Answer:
12)
(9y +7)=(2y +98)( Because vertically opposite angle is always equal)
9y - 2y = 98-7
9y - 2y = 98-7
7y= 91
y =13
<em>ther</em><em>fore</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>1</em><em>3</em>
<em>(</em><em>9</em><em>y</em><em> </em><em>+</em><em> </em><em>7</em><em>)</em>
9*13+7
117+7
124
(2y +98)
2*13+98
26+98
124
x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y
