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galina1969 [7]
4 years ago
13

6. Ed drives from Jefferson to Holden, a distance of 250 miles. He then travels on to

Mathematics
1 answer:
andreev551 [17]4 years ago
6 0

Answer:

The constant speed with Ed is travelling is 60 mile per hour

Step-by-step explanation:

Given as :

The distance cover to travel from Jefferson to Holden is (D1) 250 miles

The distance cover to travel from Holden to Paxton is (D2) 50 miles

Total time taken to complete entire journey = T = 5 hours

Let The constant speed of Ed = S mph

Time = \frac{Distance}{Speed}

Or, Time = \frac{D1}{S}  + \frac{D2}{S}

Or, 5 hour =  \frac{250}{S}  + \frac{50}{S}

Or, 5 × S = 250 + 50

So,  5 × S = 300

∴           S = \frac{300}{5}

I.e         S = 60 mph

Hence , The constant speed with Ed is travelling is 60 mile per hour Answer

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Step-by-step explanation:

To find the Surface Area of the cylinder, we will need to solve for the area of both bases and the rectangle around the cylinder. We can do this by:

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8 0
3 years ago
Find the maximum rate of change of f at the given point and the direction in which it occurs. f(p, q) = 8qe−p + 4pe−q, (0, 0) ma
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Answer:

Step-by-step explanation:

Given \ f (p,q) = 8qe^{-p} + 4pe^{-q}  \  where \ P_o(0,0) \\ \text{thus the gradient of f is: }  \\ \\  \bigtriangledown f(p,q) = \Big(\dfrac{\partial f}{\partial p}, \dfrac{\partial f}{\partial q} \Big) \\ \\  \dfrac{\partial f}{\partial p} = -8qe^{-p} + 4pe^{-q} \\ \\ \dfrac{\partial f}{\partial p} = 8qe^{-p} - 4pe^{-q}  \\ \\  Then: \bigtriangledown f(p.q) = (-4qe^{-p}+ 8qe^{-q}, 4qe^{-p}- 8qe^{-q}) \\ \\ f(0,0) = (-4*(0)e^{-0}+ 8*(0)e^{-(0)}, 4*(0)e^{-(0)}- 8*(0)e^{-(0)})  \\ \\  = (0+8,4-0)  = (8.4)

\Big| \Big | \bigtriangledown f(0,0) = \sqrt{(8)^2+4^2}  \\ \\ = \sqrt{64+16} \\ \\ =  \sqrt{80}

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3 years ago
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The equation of a plane with normal vector <7,-1,5> passing through a given point P(xp,yp,zp) is
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