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dedylja [7]
3 years ago
11

Can someone pls help me I think I know the answer but still

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

b y=9000(1+3.5)20

Step-by-step explanation:

y=a(1+r)t

yer welcome

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What is the value of n when 7n – 18 = 5n + 6?
kirill [66]

Answer:

n=12

Step-by-step explanation:

7n-18 =5n+6

+18 to both sides

7n=5n+24

-5n from both sides

2n=24

divide by 2

n=12

3 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation. 6x^2-2x+36=5x^2+10x
Oduvanchick [21]

Answer:

x = 6

Step-by-step explanation:

Given

6x² - 2x + 36 = 5x² + 10x ( subtract 5x² + 10x from both sides )

x² - 12x + 36 = 0 ← in standard form

This is a perfect square of the form

(x - a)² = x² - 2ax + a²

36 = 6² ⇒ a = 6 and 2ax = (2 × 6)x = 12x, hence

(x - 6)² = 0

x - 6 = 0 ⇒ x = 6

6 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
If f(x) = x2 - 1 and g(x) = 2x - 3, what is the domain of (fog)(x)?
ladessa [460]

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

         = (2x - 3)²

         = 4x² + 9 - 12x - 1

        = 4x² - 12x + 8

       = 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

<u>brainly.com/question/2458431</u>

4 0
2 years ago
Can someone please help I pay £100
Flura [38]

Answer:

The new points to the triangle will be:
A(1,4)\\ B(1,1)\\ C(-1,1)

Step-by-step explanation:

Because the reflection point is at x=2, all x values will subtract their distances from x=2 to get their new values. The y values remain the same.

The starting values are:

A(3,4)\\ B(3,1)\\ C(5 ,1)

Point A is 1 unit away from x=2, so we'll subtract 1 from 2 to get the new x value: 2 - 1 = 1, so A(1,4).

 

Point B is also 1 unit away from x=2, so we'll subtract 1 from 2 to get the new x value: 2 - 1 = 1, so B(1,1).

Point C is 3 units away from x=2, so we'll subtract 3 from 2 to get the new x value: 2 - 3 = -1, so C(-1,1).

3 0
2 years ago
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