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tangare [24]
3 years ago
9

A. m=3h-24B. m=3h+24C. m=8hD. m=8h+8please help me

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0
Formular for line graph is
y=mx+b

Find the gradient first
{ \frac{y1-y2}{x1-x2} } \\ \\ = { \frac{0-80}{0-10} } \\ \\ = { \frac{-80}{-10} } \\ \\ = 8

Substitude the gradient to the formular

80=8(10)+b \\ \\ b=0

∴ m=8h is the equation of the graph.

Answer is C.
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HELP! &lt;3<br><br> I have other questions as well not yet posted, if you'd like more points! :3
ratelena [41]

Option B: \frac{AB}{BC}=\frac{AE}{ED} is sufficient to prove that BE ll CD

Explanation:

Given that ACD is a triangle.

The line EB intersects the sides AC and AD of the triangle.

The point E intersect the side AD and B intersect the side AC.

We need to prove that BE ll CD

Then, the side splitter theorem states that "If a line intersects two sides of a triangle and divides the sides proportionally, the line is parallel to the third side of the triangle".

From the side splitter theorem, the line EB intersects the two sides of the triangle AC and AD and divides the sides proportionally.

Thus, the proportion of the sides is given by

\frac{AB}{BC}=\frac{AE}{ED}

This proportionality shows that the line is parallel to the third side of the triangle.

Hence, \frac{AB}{BC}=\frac{AE}{ED} is sufficient to prove that BE ll CD

Therefore, Option B is the correct answer.

3 0
3 years ago
11. Kamala borrowed 26400 from a bank to buy a scooter at a rate of 15% per annum compounded yearly. What amount will she pay at
oee [108]
<h2>Answer </h2>

Amount (A) = P[1 + (r/100)]n

Principal (P) = ₹ 26400

Time period (n) = 2 years 4 months

Rate % (R) = 15% compounded annually

<h3>Steps </h3>

First, we will calculate Compound Interest (C.I) for the period of 2 years

A = P[1 + (r/100)]n

= 26400[1 + (15/100)]²

= 26400[(100/100) + (15/100)]²

= 26400 × 115/100 × 115/100

= 26400 × 23/20 × 23/20

= 26400 × 1.3225

= 34914

C.I. = A - P

= 34914 - 26400

= 8514

Now, we will find Simple Interest (S.I) for the period of 4 months

Principal for 4 months after C.I. for 2 years = ₹ 34,914

<h3>We know that ,</h3>

S.I = PRT/100

Here T = 4 months = 4/12 years = 1/3 years

S.I. for 4 months = (1/3) × 34914 × (15/100)

= (1/3) × 34914 × (3/20)

= 34914/20

= 1745.70

Total interest for 2 years 4 months = 8514 + 1745.70

= 10259.70

Total amount for 2 years 4 months = 26400 + 10259.70

= ₹ 36659.70

<h3>So , the correct answer is ₹ 36659.70 . </h3>

6 0
2 years ago
Read 2 more answers
A multiple regression model has ___
Salsk061 [2.6K]

Answer:

C. More than one independent variable

Step-by-step explanation:

The difference between linear regression model and multiple regression model is that the linear regression has just one independent variable which is use to determine the dependent variable. While the multiple regression model has at least two or more independent variable which is use to determine the dependent variable.

5 0
3 years ago
What is 0.5, 3/16, 0.75, and 5/45 from least to greatest
BartSMP [9]

5/45, 3/16, 0.5, & 0.75

8 0
3 years ago
Which equations represent exponential growth? Which equations represent exponential decay? Drag the choices into the boxes to co
Norma-Jean [14]

Answer:

Exponential growth functions are:

A=20000(1.08)^{t}

A=40(3)^{t}

A=1700(1.07)^{t}

Exponential decay functions are:

A=80(\frac{1}{2})^{t}=80(0.5)^{t}

A=1600(0.8)^{t}

A=1700(0.93)^{t}

Step-by-step explanation:

Given:

An exponential function is of the form y=ab^{x}, where, a\ne 0.

Now, if a > 0 and b > 1, then the exponential function represent exponential growth.

If a > 0 and 0 < b < 1, then the exponential function represent exponential  decay.

Let us check each function now.

Option 1: A=20000(1.08)^{t}

Here, a = 20000, b = 1.08

As 1.08 > 1, the function is exponential growth.

Option 2: A=80(\frac{1}{2})^{t}=80(0.5)^{t}

Here, a = 80, b = 0.50

As 0.5 < 1, the function is exponential decay.

Option 3: A=1600(0.8)^{t}

Here, a = 1600, b = 0.8

As 0.8 < 1, the function is exponential decay.

Option 4: A=40(3)^{t}

Here, a = 40, b = 3

As 3 > 1, the function is exponential growth.

Option 5: A=1700(1.07)^{t}

Here, a = 1700, b = 1.07

As 1.07 > 1, the function is exponential growth.

Option 6: A=1700(0.93)^{t}

Here, a = 1700, b = 0.93

As 0.93 < 1, the function is exponential decay.

5 0
3 years ago
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