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Andrews [41]
3 years ago
11

United States flags come in different sizes. Standard dimensions for a flag are a length to width ratio of 1 : 9 to 1. Flag 1 ha

s a width of 1 foot and a length of 1.9 feet and Flag 2 has a width of 2.7 feet. What is the correct length of Flag 2?
Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

5.13 feet

Step-by-step explanation:

So, we have the full dimensions of flag #1, and we have the partial dimensions of flag #2, which should follow the same ratio as flag #1, since not indicated otherwise.

When you need to compare dimensions like that, the easiest way to proceed is to do a cross-multiplication. Let's say x is the length of flag #2 we're looking for.  It's ratio over the width of flag #2 will be the same as the ratio of the length of flag #1 over its width, so:

\frac{x}{2.7} = \frac{1.9}{1}

If we isolate x, we have x = (2.7 * 1.9) / 1 = 5.13 feet

Which makes sense since we know the result should be a bit less than 2.7 times 2.

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Leah drives 45 miles per hour for 2 hours then 32 miles per hour for 90 minutes . What is her average speed
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 =39.42857143 miles per hour

Step-by-step explanation:

To find the average speed, we need to the total distance and the total time

Distance 1

45 miles for 2 hours

45*2 = 90 miles

Distance 2

90 minutes * 1 hour/60 minutes = 1.5 hours

32 miles * 1.5 hours =48 miles

The total distance = 90+48 = 138 miles

The total time = 2 +1.5 = 3.5 hour

The average speed = total distance/ total time

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Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
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ollegr [7]

Answer:

a. ∠D'A'B'

Step-by-step explanation:

From the graph it is clear that the transformation doesn't affect the size and shape of the figure ABCD.

Only the coordinates of the points are changed with the length of each side remaining the same.

Hence the corresponding angle values will also remain unaltered.

∴ ∠DAB = ∠D'A'B'

5 0
3 years ago
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