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Troyanec [42]
3 years ago
8

Simplify the expression 5+(4+x)

Mathematics
2 answers:
photoshop1234 [79]3 years ago
4 0
5 + 4x
I think that’s right
lara31 [8.8K]3 years ago
4 0

Answer:

5 + (4 + x) = 5 + 4 + x = 9 + x

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1.2, 3, 7.5, 18.75, ...<br><br> Which formula can be used to describe the sequence?
Nady [450]

Answer:

The formula is:

a_n=1.2(\frac{5}{2})^{n-1}

Step-by-step explanation:

The geometric sequences are those in which the division between the terms a_{n + 1} and a_n of the sequence are equal to a constant common reason called "r"

The geometrics secencias have the following form:

a_n=a_1(r)^{n-1}

Where a_1 is the first term of the sequence

In this sequence we have the following terms

1.2, 3, 7.5, 18.75

Then notice that:

\frac{3}{1.2}=\frac{5}{2}\\\\\frac{7.5}{3}=\frac{5}{2}\\\\\frac{18.75}{7.5}=\frac{5}{2}

Then:

r=\frac{5}{2}  and a_1=1.2

Finally the formula is:

a_n=1.2(\frac{5}{2})^{n-1}

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3 years ago
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Step-by-step explanation:

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Find the factors of f(x), given that x = −2 is a zero. HELP PLEASE!!
seropon [69]

Answer:

First Option is correct.

(x+2)(x+3)(x-4)

Step-by-step explanation:

Given:

The given factor is.

f(x)=x^{3}+x^{2}-14x-24

We need to find the factors of given factor.

Solution:

f(x)=x^{3}+x^{2}-14x-24

Substitute (-4x-10x) in the place of -14x

f(x)=x^{3}+x^{2}-4x-10x-24

Rearrange the equation:

f(x)=(x^{3}-4x)+(x^{2}-10x-24)

Now we factorised the above equation.

The factors of x^{2} -10x-24=(x+2)(x-12)

Now we substitute (x+2)(x-12) in the place of x^{2} -10x-24

And in the place of x^{3}-4x=x(x^{2}-4)

f(x)=x(x^{2}-4)+(x+2)(x-12)

Simplify x^{2} -4=x^{2} -(2)^{2} = (x+2)(x-2)

f(x)=x[(x+2)(x-2)]+(x+2)(x-12)

Common factor for above function (x+2)

f(x)=(x+2)[x(x-2)+(x-12)]

Simplify.

f(x)=(x+2)[x^{2}-2x+x-12]

f(x)=(x+2)(x^{2}-x-12)

The factor of x^{2}-x-12=x^{2}-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)

So the factors of the function.

f(x)=(x+2)(x-4)(x+3)

Therefore, the factors of the given function are (x+2)(x-4)(x+3)

4 0
3 years ago
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