Answer:
D. 30%?
I'm not 100% sure but I think its D. Sorry if it's wrong.
Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
it would be 16 times larger
Answer:
(-1,0)
step-by-step explanation:
(-6,3)
right 5
(-1,3)
down 3
(-1,0)
Answer:
-a + b
Step-by-step explanation: