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Rudik [331]
3 years ago
12

After how many years will £6,000.00 yield a simple interest of £900.00 at 3%​

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

add 1 Century to divide £6 000 000

____ [38]3 years ago
4 0

Answer:

the answer to your question is 105 I think sorry if it's not

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What is the y-value in the solution to this system of linear equations? 4x + 5y = -12 -2x + 3y = -16 them -4 -2 2​
VikaD [51]

Answer: I think it's y= -4

Step-by-step explanation:

5 0
3 years ago
An aircraft jet engine has a thrust of I80N. What impulse is produced<br> in 30 S?
neonofarm [45]

The impulse that was produced by this aircraft jet engine is 5,400 Ns.

<u>Given the following data:</u>

  • Thrust = 180 Newton.
  • Time = 30 seconds.

To determine the impulse that was produced by this aircraft jet engine:

<h3>How to calculate impulse.</h3>

Mathematically, impulse is given by this formula:

I = Ft

<u>Where:</u>

  • F is the force or thrust.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

I = 180 \times 30

Impulse, I = 5,400 Ns.

Read more on impulse here: brainly.com/question/16750406

8 0
2 years ago
Which of the following polygons is not a regular polygon?
Shkiper50 [21]

Answer:

b

Step-by-step explanation:

polygons is a plane figure that is described by a finite number of straight line segments connected to form a closed polygonal chain or polygonal circuit

6 0
3 years ago
HURRYYY PLEASEEEE
masha68 [24]
The answer is 7/25.
4 0
3 years ago
Which expression is equivalent to
Nat2105 [25]

Answer : The correct option is \frac{1}{36a^{4}b^{10}}

Step-by-step explanation :

According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).

The given expression is:

[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}

=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}

=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]

=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]

=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]

=\frac{1}{36a^{4}b^{10}}

Thus, the given expression is equivalent to \frac{1}{36a^{4}b^{10}}

5 0
4 years ago
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