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xeze [42]
3 years ago
11

What is y=7/3x+5? x=-3

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0
Hello!

Ok so we have y= 7/3x + 5 and initial condition of x=-3 so we just plug -3 in for x and chug along at this point! :)

y=(7/3)*(-3/1)+5= -7+5 = -2

Hope this helps! Any questions please just ask! Thank you!!
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Evaluate each expression when a= - 4 and b= 3 ab
Andrews [41]

Answer:

-12

Step-by-step explanation:

<u>Step 1:  Substitute</u>

ab -> -4 for a and 3 for b

(-4) * (3)

<em>-12</em>

Answer:  -12

6 0
3 years ago
T he equation for a parabola with directrix y = –p and focus (0, p) is:
zhuklara [117]

The equation for a parabola with directrix y = –p and focus (0, p)

The distance between vertex and directrix is P

Also the distance between vertex and focus is also P

Focus (0,p) so focus lies on y axis

Directrix line is paralled to focus point

So Directex crosses the x axis .

Hence line of symmetry lies is the y-axis.

The graph is attached below.


3 0
3 years ago
What is the place value for 3 in 318,472,008
VikaD [51]
Salutations!

What is the place value for 318,472,008

The number 3 is in the place as hundred million.

In the numeric form, we can write the number as ------

300, 000, 000.

Hope I helped.
6 0
3 years ago
You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
3 years ago
Help me please this is due in a couple minutes
dsp73

Answer:

v=0.79x+3.99

f=1.89x+5.49

combined cost: 2.68×+9.48

8 0
3 years ago
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