2 years ago

Which is a correct way to find f(3) when f(x) = 2x27

1 answer:

dalvyx [7]2 years ago

5 0

The answer to = 2x27 is f(x)

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expeople1 [14]

Answer:

$\large\boxed{8x^3+125=(2x+5)(4x^2-10x+25)}$

Step-by-step explanation:

$8x^3+125=2^3x^3+5^3=(2x)^3+5^3\\\\\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+5)((2x)^2-(2x)(5)+5^2)\\\\=(2x+5)(4x^2-10x+25)$

3 0

3 years ago

maxonik [38]

Step-by-step explanation:

after you draw a unit circle you will find the answer

cosec(3pi)=1/sin(3pi)

sin3pi=sinpi=0

so cosec3pi=1/0 which is undefined.

3 0

2 years ago

ki77a [65]

Answer:

jus trynna get points

Step-by-step explanation:

5 0

2 years ago

Lynna [10]

Angles 6 and 7, because they are alternate along the transversal.

Also angles 1 and 4.

6 0

2 years ago

____ [38]

The answer is D I believe

3 0

2 years ago

Which is a correct way to find f(3) when f(x) = 2x27​