First we need to find k ( rate of growth) The formula is A=p e^kt A future bacteria 4800 P current bacteria 4000 E constant K rate of growth? T time 5 hours Plug in the formula 4800=4000 e^5k Solve for k 4800/4000=e^5k Take the log for both sides Log (4800/4000)=5k×log (e) 5k=log (4800/4000)÷log (e) K=(log(4,800÷4,000)÷log(e))÷5 k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours A=p e^kt A ? P 4000 K 0.03646 E constant T 15 hours Plug in the formula A=4,000×e^(0.03646×15) A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
