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GarryVolchara [31]
3 years ago
8

Which equation can be used to describe the direct variation function between E, the total earnings in dollars, and h, the number

of hours worked? E = 1.5h E = 7.5h E = 13h E = 15h

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Let us take a sharp point for the graph.

In 4 hours total earning is $30.

Therefore, earnings per hours would be 30/4 = $7.5 per hour.

Are given direct variation between Total earnings(E) and Number of hours worked(h).

So, we can setup a direct variation as

Total earnings = Earning each hour * Number of hours.

Therefore, direct variation function would be

E=7.5*h.

Therefore, the direct variation function between E, the total earnings in dollars, and h, the number of hours worked is E = 7.5h.


Sati [7]3 years ago
8 0

Answer:

The answer is E=7.5h hope it helps

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The world brand of rivet placement is 11209 rivets in 9 hours and belongs to J. Mair of Ireland. If another person places 11209
Ilya [14]

Answer:

4.74 hours

Step-by-step explanation:

Given that both person have to place same number of rivets that is

11209

first person take 9 hours to complete the work

hence 1 hour work of 1st person is \frac{1}{9} of total work

second person takes 10 hours to complete the same work

hence 1 hour work of 2nd person is \frac{1}{10}

Now if both work together then

1 hour work of both person = \frac{1}{9} +\frac{1}{10} =\frac{19}{90}

thus working together they need \frac{90}{19} hours = 4.74 hours to complete the whole work which is placing 11209 rivets  

5 0
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Solve using order of operations (9 + 33 – 6 ) ÷ 6 – 32
marusya05 [52]

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-26

Step-by-step explanation:

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Let X be a normal random variable with mean 3 and variance 4. (a) Find the probability P(2 < X < 6). (b) Find the value c
Vanyuwa [196]

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

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with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

4 0
3 years ago
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