Answer:
Step-by-step explanation:
2/3 ÷ 1/3
=2/3 × 3/1 (recipracol)
=6/3
=2
Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
I don’t think this is algebra 2 but ok
37
I used the formula (32°F − 32) × 5/9 = 0°C (but ofc replaced the numbers with 99)
Yeah and i rounded 98.6 to 99. 99 Fahrenheit is 37.2222... so i rounded it down to 37. So i think the answer is 37.
Answer:
la vida mafio
Step-by-step explanation:
mafioaso.
Step-by-step explanation:
