Since this question is asking for an inequality formula, let's get started.
Seven subtracted from c=c-7 (it is NOT 7-c because then it would ask c subtracted by seven)
Less than means that the c-7 is less than -16, so it would face this way <
The final answer is c-7<-16
Think of the squares of the whole numbers.
0^2 = 0
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
39 is between 36 and 49, so sqrt(39) is between 6 and 7.
Answer:
<h2>693 m²</h2>
Step-by-step explanation:
This is a parallelogram.
The formula of an area of a parallelogram:
![A=bh](https://tex.z-dn.net/?f=A%3Dbh)
<em>b</em><em> - base</em>
<em>h</em><em> - height</em>
From the graph we have <em>b = 21m</em> and <em>h = 33m</em>.
Substitute:
![A=(21)(33)=693\ m^3](https://tex.z-dn.net/?f=A%3D%2821%29%2833%29%3D693%5C%20m%5E3)
17 is next in the pattern
If we know your Pythagorean Triples we can immediately recognize that the last choice is a right triangle:
8² + 15² = 17²
If you don't know your Pythagorean Triples, it's worth learning the first few off the list because teachers use them in problems all the time. But for now let's just exhaustively check the Pythagorean Theorem for each triangle. We don't have to multiply everything out; we can analyze the common factors. If two have a common factor that the third one doesn't have, there's no way for the Pythagorean Theorem to add up.
Clearly 5²+15² is a multiple of 5 but 18² isn't so that one isn't a right triangle.
6²+12² is a multiple of 6, 16² isn't a multiple of 6, not an RT.
15²-5² is a multiple of 5, 13² isn't, no joy.
8²+15² = 64 + 225 = 289 = 17² -- that's a real right triangle, a valid Pythagorean Triple.