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Sphinxa [80]
3 years ago
14

This recursive formula represents a geometric sequence: a1 = 2 an = 6(an − 1); for n ≥ 2 Select the geometric sequence that can

be constructed from the given recursive formula, and select the explicit formula for the sequence.
Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

f(n)=2X6ⁿ⁻¹

Step-by-step explanation:

a₁=2

aₙ=6aₙ₋₁ for n≥2

a₂=6a₂₋₁=6a₁=6*2=12

a₃=6a₃₋₁=6a₂=6*12=72

a₄=6a₄₋₁=6a₃=6*72=432

This is a geometric sequence with:

First term, a=2

Common ratio, r= 12/2=6

For a geometric sequence, the nth term is given by:

Uₙ=arⁿ⁻¹

Uₙ=2X6ⁿ⁻¹

Therefore, the explicit formula for the sequence f(n) is given as:

f(n)=2X6ⁿ⁻¹

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If a 150-pound teenager eats 5.5 pounds of food per day, is that proportional to a 250-pound panda eating 40 pounds of bamboo a
taurus [48]

Answer: No It's not proportional as the constant of proportionality for both of them.are different.

Step-by-step explanation:

For the first part of the question, a 150-pound teenager eats 5.5 pounds of food per day, we've to calculate the constant of proportionality. This will be:

y = kx

150 = 5.5k

k = 27.27

For the second part of the question, a 250-pound panda eats 40 pounds of bamboo a day. we've to calculate the constant of proportionality. This will be:

y = kx

250 = 40k

k = 250/40

k = 6.25

This shows that the 150-pound teenager eats 5.5 pounds of food per day, is not proportional to a 250-pound panda eating 40 pounds of bamboo a day because th e value of k are different.

6 0
3 years ago
A college has 1503 students, of which 5/9 are on modern apprenticeship courses. How many students are not on modern apprenticesh
Mila [183]
Btw that is a 668 :)

5 0
3 years ago
Susie plans to run 2 miles per day the first week and then increase the daily distance by a half a mile each of the following we
AlekseyPX

Due to length restrictions, we kindly invite to see the explanation below to know the answer with respect to each component of the question concerning linear equations.

<h3>How to determine a linear equation describing the daily distance of a runner</h3>

In this question we need to derive an expression of the <em>daily</em> distance as a function of time. Now we proceed to complete the components:

  1. <em>Linear</em> equations have an <em>independent</em> variable (t - time) and a dependent variable (x - daily distance).
  2. We notice that the daily distance increases linearly in time, then then we have the following pattern:

    t          1            2            3             4            5              6
    x          2          2.5          3           3.5           4             4.5
  3. The equation that represents the n-th term of the sequence is x(n) = 2 + 0.5 · (n - 1).
  4. The week when Susie will run 10 miles per day is:

    10 = 2 + 0.5 · (n - 1)
    8 = 0.5 · (n - 1)
    n - 1 = 16
    n = 17

    Susie will run 10 miles per day in the 17th week.
  5. It is not reasonable to think that pattern will continue indefinitely as it is witnessed in the difficulties experimented by <em>fastest</em> runners in the world to increase their <em>peak</em> speeds.
  6. A marathon has a distance of 26 miles, then we must solve the following equation:

    26 = 2 + 0.5 · (n - 1)
    24 = 0.5 · (n - 1)
    48 = n - 1
    n = 49

    Susie should start her training 49 weeks before the marathon.

To learn more on linear equation: brainly.com/question/11897796

#SPJ1

7 0
2 years ago
Ellen drove 357.3 miles.for each gallon of gas,the car can travel 21 miles.select a reasonable estimate of the number of gallons
kari74 [83]
Just a little over 17 gallons was used
7 0
3 years ago
www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb
damaskus [11]

Answer:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

Step-by-step explanation:

For this problem we have the following parameters given:

\mu = 40, \sigma =8

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

z=\frac{X-\mu}{\sigma}

And replacing we got:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

5 0
3 years ago
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