All categories

3 years ago

The licene fee for a car which costs $9,200 is $82. at the same rate, what is the licence fee for a car that cost $9,900.

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Step 1: Assign variable for the unknown that we need to find.

Let 'x' be the licence fee for a car that cost $9,900.

Step 2: Set up a proportion based on the given information.

$\frac{x}{9900} =\frac{82}{9200}$

Step 3: Solve for x

To get x alone we need to undo whatever is done to x. So multiply 9900 on both sides of the equation.

$\frac{9900x}{9900} =\frac{9900*82}{9200}$

Simplifying fraction on both sides of the equation, we get...

$x=88.24$

Conclusion:

$88.24 is the licence fee for a car that cost $9,900.

You might be interested in

Anybody want to role play ???

Afina-wow [57]

Answer:

Thats smarttt

Step-by-step explanation:

You phrased it so it would get pass the brainly bots system, kudos to you!

8 0

3 years ago

Find a formula for the nth term

Tomtit [17]

Answer:

an =a1+(n−1)d

Step-by-step explanation:

4 0

2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

2 years ago

Through (-1,5) , perp to y =1/9x+2 write the slope intercept form for the equation

ycow [4]

Answer:

y=-9x-4

Step-by-step explanation:

Perpendicular lines meet the following condition:

m2*m1= -1 (a)

where m is the slope of a line

m1 is given through equation of line 1, y =1/9 x+2

m2 must be -9 -> from eq. (a)

The Line has the following equation: y=mx+b, where m=-9 and the b is the interception with y axis.

Evaluating the above equation in (-1,5) we have the following equation

5= -9*(-1)+b, we have b=-4

The line has the following equation

y=-9x-4

Slope intercept form

4 0

2 years ago

Read 2 more answers

5.4= 0.9x A.6.3 B. 6 C. 7.3 D.12

Marat540 [252]

Answer:

5.4=0.9x

4 0

3 years ago

Read 2 more answers