The lcf of 8 and 56 is 2, the lcf of 12 and 30 is 2, the lcf of 16 and 24 is 2, and the lcf of 9 and 15 is 3.
Answer:
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Explanation:
The text and the model are garbled.
This is the question amended:
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<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>
<em>H(t) = -10 cos(2π/150 t)+10</em>
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<em>When does Hyun Woo first reach a height of 16 m?</em>
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<h2>Solution</h2>
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When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:
- <em>16 = -10 cos(2π/150 t)+10</em>
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Then you must find the lowest positive value of t that is a solution of the equation.
Solve the equation:
- <em>16 = -10 cos(2π/150 t)+10</em>
- t = 52.86s ≈ 53 s ← answer
Answer:
Step-by-step explanation:
5/6 + 1/8 + 3/4 = 1 17/24
Option A is the correct answer
Mult. the 2nd eqn by 6 and then add this "new" equation to the 1st given eqn:
-6x + y = -2
6x -18y = 54
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-17y = 52, or y = -52/17. Subst. this value of y into either equation to find the value of x.
Answer:
cot∅ = (-2√30)/7.
Step-by-step explanation:
Given the value of csc∅ = -13/7 and ∅ is in quad III.
We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).
It means y = -7, r = 13.
We know x² + y² = r².
x² = r² - y²
x² = (13)² - (-7)² = 169 - 49 = 120.
x = √120 = 2√30.
we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.
Hence, cot∅ = (-2√30)/7.