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Sliva [168]
3 years ago
5

Please help please help

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

I'm not sure if i am correct but i would say

[ 0,1 ]

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Which equation represents the line shown on the coordinate grid below ?
RoseWind [281]

Answer: B

Step-by-step explanation:

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2 years ago
7 divided by 982 long division
Ne4ueva [31]

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140r2

Step-by-step explanation:

7 0
3 years ago
At an animal shelter there are 15 dogs 12 cats 3 snakes and 5 parakeets which animal has 80% of the number of another animal
Tomtit [17]
12 times 100 divided by 15 equals 80
So the answer is cats
3 0
3 years ago
Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
3 years ago
Please help on question 17 with step by step instructions <br> Thanks in advance xx
shutvik [7]
Let x = Initial Price

If we increase x by 5%, we are adding 0.05x

Therefore, the new price = x + 0.05x = 1.05x

If the ticket has increased by £2.30, £2.30 is 5% of the initial price, or 0.05x

0.05x = 2.30

x = 2.30/0.05

x = 46

Therefore, the price of the ticket before the increase was £46

You can also check this backwards by doing 46*0.05 = 2.30
6 0
3 years ago
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