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3 years ago

Please help please help

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

I'm not sure if i am correct but i would say

[ 0,1 ]

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Plz help!!! i’ll mark brainliest!!!!

makkiz [27]

Step-by-step explanation:

go to rcboe.org sorry if it doesn't work

8 0

3 years ago

Need help! Will mark Brainiest!

kicyunya [14]

Option B: $y=-\sqrt[3]{x-4}+7$ is the new equation

Explanation:

The given equation is $y=-\sqrt[3]{x}$

We need to find the new graph which is shifted 7 units up and 4 units right.

First, we shall shift the graph 7 units up.

The general formula to shift the graph b units up is given by

$y=f(x)+b$

Thus, to shift the graph 7 units up, let us substitute $b=7$ and $f(x)=-\sqrt[3]{x}$ in the general formula, we have,

$y=$-\sqrt[3]{x}$+7$

Now, we shall shift the graph 4 units right.

The general formula to shift the graph b units right is given by

$y=f(x-b)$

Thus, to shift the graph 4 units right, let us substitute $b=4$ and $f(x)=$-\sqrt[3]{x}+7$$ in the above equation, we have,

$y=-\sqrt[3]{x-4}+7$

Therefore, the new equation is $y=-\sqrt[3]{x-4}+7$

Therefore, Option B is the correct answer.

5 0

3 years ago

Rationalize <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%20%5Csqrt%7B7%7D%20%2B%203%20%5Csqrt%7B3%7D%20%20%7D%20"

Ivahew [28]

$\dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} }$

$= \dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} } \times \dfrac{2 \sqrt{7} - 3 \sqrt{3}}{2 \sqrt{7} - 3 \sqrt{3}}$

$=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{(2\sqrt{7})^2 - (3\sqrt{3})^2}$

$=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{28 - 27}$

$=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{1}$

$=2 \sqrt{7} - 3 \sqrt{3}$

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3 years ago

kayla has saved up 147 and she sells movies for .18 each and needs to get to 750 , how many movies does she need to sell to get

zheka24 [161]

I think the answer is 3350

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3 years ago

Plz help.......................

slamgirl [31]

The second graph, B is the answer

8 0

4 years ago