The value of tan³ θ + 2 = 3
Solution is in attachment !
Answer:
(x+5)^2+(y-12)^2=256
Step-by-step explanation:
Comparing the given (x+5)^2+(y-12)^2=256
to (x - h)^2 + (y - k)^2 = r^2,
we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.
Alright, so first we need to establish two things.
First, the compliment of a set is like the extreme opposite; everything that is not in set B will be in the complement.
Second, we need to find out what B is.
Okay, so B is everything that is greater than 2, that's given. That includes 3, 4, and 5. B = {3, 4, 5}. There are three items in this set.
The numbers that aren't included are 1 and 2. The complement of B, let's call this C I guess, is C = {1, 2}. There are 2 items in this set.
The answer, I believe, is <em>two</em>. Hope this helps!
Hello!
To find cosine, use the formula cos = adjacent / hypotenuse.
According to angle B, adjacent of angle B is side A, and the hypotenuse is side c because the hypotenuse is always opposite the right angle.
Therefore, the cosine of angle B is a/c.
Answer:
Step-by-step explanation:
P(tail) = 
P(2) = 
P(tail and 2 ) = × =
