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3 years ago

A line intersects the point (-11, 4) and has

Mathematics

1 answer:

alekssr [168]3 years ago

5 0

Answer: Point slope form is y-y1=m(x-x1)

Step-by-step explanation:

Here y1=4

x1=-11

m i.e slope=-2

And there you go.

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Lmk asap please cuz I need it by tonight

OLEGan [10]

Answer: 20

Step-by-step explanation:

2x^2 + 4y=

2(2)^2 + 4(3)=

2(4)+12=

8+12=20

7 0

2 years ago

True or false (picture provided)

Eddi Din [679]

False. That does not satify the equation

8 0

3 years ago

Read 2 more answers

Find the value of each expression<br><br> 3[ (20 - 4) / 2]<br><br> 5(9) / (8 / 4)

storchak [24]

3 [ (20-4) / 2 ]= 3 * 16/2= 3 x 8 =24

5,(9)=5 9/9= 54/9=6

6/8/4= 6/2=3

4 0

3 years ago

Read 2 more answers

A group of students was randomly divided into two subgroups. One subgroup took a test in the morning, and the other took the sam

BARSIC [14]

Answer:C

Step-by-step explanation: I believe it is C according to my calculations

3 0

3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

4 0

2 years ago