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cricket20 [7]
3 years ago
6

4 Performance Assesment Form B

Mathematics
1 answer:
jeka943 years ago
8 0

Answer:

b

Step-by-step explanation:

i hope this helps

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A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
Fofino [41]
Follow the given formula.  The initial amount of money invested, P, becomes 2P (same thing as "doubles) after t years.  Since compounding is quarterly, n=4.  The annual interest rate is 12%.  That is, r=0.12.

Then we have 2P = P (1 + 0.12/4)^(4t) and need only solve for time, t.

Simplifying the above equation:  2 = (1.03)^(4t)

We must isolate 4t, and then isolate t.  To do this, take the common log of both sides of the above equation.  We get:

log 2 = (4t) log 1.03.  This gives us 4t = [log 2] / [log 1.03], or

4t =  23.4498

Dividing both sides by 4, we get     t = 5.86 (years).
7 0
4 years ago
6x.<br> I need help on this ASAP
goblinko [34]

Answer:

Where's the question?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Toni gives a cashier a $20 bill he is buying an item for $4.79 how much money should tony get back
Effectus [21]

Answer:

$15.21

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If I had a 2% solution, added 2 ounces to a gallon (128 ounces) What is the final concentration of the solution.
Ne4ueva [31]
<span>A 2% solution of chlorohexidine added to 126 oz of water. The total oz 128.

Solute: chlorohexidine, 2%=0.02
solvent: water (0%)

Concentration, C, volume V
CV=c1v1+c2v1
128C=0.02*2 + 0.00*126 = 0.04

Concentration
C=0.04/128 = 0.0003125 = 0.03125%</span>
6 0
4 years ago
with Judy jogging north and Jackie jogging west (on straight roads). When Jackie is 1 mile farther fro m the intersection than J
miskamm [114]
Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.

We convert the given information to equations, step by step.

Point 1: When Jackie is 1 mile farther from the intersection than Judy.

This means y is 1 mile more than x.

So,

y = 1 + x

Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection. 

Distance between is x+ y.

So, x+y is 2 miles more than y.

x+y = y + 2
⇒
x = 2

From point 1 we have:

y = 1 + x = 1+ 2 = 3

So,

Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
4 0
3 years ago
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