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3 years ago

7

What is the probability that a point in the rectangle below is also in the isosceles trapezoid ?

1 answer:

AleksandrR [38]3 years ago

4 0

Answer:

Read the example letter below, and answer the question that follows.

June 14, 2015

1234 Maplewood Lane

Sunnydale, MN 55003

Dear Courtney,

I hope you are doing well, and that your recent move to Sunnydale went smoothly. We all miss you greatly, but are excited for you to begin your new career in wildlife photography. I am writing to ask if you would consider writing a letter of reference for my application to the summer photography program at the local community college.

When applying to the program, I immediately thought of you as a potential reference. As my former supervisor, you have directly observed my passion for photography, and my willingness to learn more about the field. I believe that my time working with you at the photography studio was an excellent first step towards my future career in the field. The letter of reference will enable me to continue my growth and experience in photography.

I hope that you will consider writing the letter of reference, and I truly appreciate your consideration.

Regards,

Samantha Carlotta

What is the above an example of?

friendly letter

business letter

letter of reference

request letter

Step-by-step explanation:

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Without solving, determine whether the solution of x = 21 is greater than or less than 21. Explain.

astraxan [27]

Answer:

Without solving, the solution is greater than 21. The can be proven because a fraction of x is equal to 21, therefore x cannot be less than 21.

Step-by-step explanation:

7 0

3 years ago

Find the correct sum of the polynomials (6x3 − 8x − 5) + (3x3 + 6x + 2).

Advocard [28]

Answer:

$9x^3-2x-3$

Step-by-step explanation:

The question is

$(6x^3-8x-5)+(3x^3+6x+2)\\$

collect like terms

$(6x^3-8x-5)+(3x^3+6x+2)\\\\\\6x^3+3x^3-8x+6x-5+2\\\\\\9x^3-2x-3$

3 0

3 years ago

John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

3 0

3 years ago

Hi, another math addition fraction question, please help.

Irina18 [472]

Answer:

11/15

Step-by-step explanation

7 0

3 years ago

Read 2 more answers

I need help pleaseeeee Prove that: 12^13–12^12+12^11 is divisible by 7 and 19. BTW in format ______*7*19 :D

iragen [17]

Each term has a common divisor of $12^{11}$ :

$12^{13}-12^{12}+12^{11}=12^{11}(12^2-12+1)=12^{11}\cdot133$

133 = 7*19, so the number in the blanks is $12^{11}$ .

3 0

3 years ago