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Digiron [165]
3 years ago
8

PLZ HELP!!!!!!!!!!!!!! :(

Mathematics
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

D: x≥-3

Step-by-step explanation:

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Spencer made a quilt for his cousin's doll. The quilt had a 7x7 array of different color square patches. If each patch is 1 3/4
Damm [24]

Answer:

\frac{2401}{16} square inches

Step-by-step explanation:

Given:

The quilt made by Spencer had a 7×7 array of different color square patches such that each patch is 1\frac{3}{4} in long.

To find: the area of the whole quilt

Solution:

Side of each quilt = 7(\frac{3}{4})=7(\frac{7}{4})=\frac{49}{4}

Quilt is in the form of a square such that area of square is given by (side)^2

Therefore, area of quilt = (side)^2=(\frac{49}{4})^2 =\frac{2401}{16}  square inches

3 0
4 years ago
Joni has a circular garden with a diameter of 14 1/2 feet if she uses 2 teaspoons of fertilizer for every 25 square feet of gard
alina1380 [7]

Answer:

13.20 teaspoon of fertiliser needed for entire garden.

Step-by-step explanation:

Diameter of the garden = 14.50 ft

Radius of the garden = 7.25 ft

Area

[tex]A=\pi r^2[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]\pi=3.14[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]A=3.14 \times 7.25 \times 7.25[/text]

Hence

[tex]A=165.046[/text]

Area is 165.046 Sq Ft

For 25 sq ft of fields the fertiliser needed = 2 tea spoon

For 1 sq ft of fields the fertiliser needed =

[tex]\frac{2}{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed =

[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon

6 0
3 years ago
Describe the error in the work shown.
QveST [7]

Answer:

should be xy^4/4

Step-by-step explanation:

next to the last step (x^3(y^3)^4)^1/3

6 0
3 years ago
Hhh I’m very bad at math
barxatty [35]

Answer:

See below;

Step-by-step explanation:

21 . Consider an exponential function;

Exponential Function in Form - y = a * b^x, where, a - start value, b - growth factor, x - time,\\\\Now y = f ( x ), in Other Words,\\p ( t ) = 300 * ( 0.5 )^t - Given,\\\\Through Substitution - f ( x ) = p ( t ), a = 300, b = 0.5, x = t,\\\\Conclusion ; 300 - ( start value ) - Starting Amount of Milligrams of Compound,\\0.5 - Milligrams Compound Decreases by

<em>Solution; Provided Directly Above</em>

3 0
3 years ago
What is the value of StartFraction 6 Over x EndFraction + 2x2, when x = 3?
Vesna [10]
D. 20
(6/X) + 2x^2 =
(6/3) + 2(3^2) =
2 + 2(9) =
2 + 18=
20
5 0
2 years ago
Read 2 more answers
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