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3 years ago

Ahhhh please help! T.T

Mathematics

2 answers:

Marizza181 [45]3 years ago

5 0

Answer:70

Step-by-step explanation: The exterior angles (2x+12) and (2x) have corresponding interior angles 180-(2x+12) and 180-(2x)Triangle ABC has the following interior angles A = 112B = 180 - 2xC = 180 - (2x+12) = 180-2x-12 = 168-2xAdd up the interior angles for A,B,C and set the result equal to 180. Solve for xA+B+C = 180(112)+(180-2x)+(168-2x) = 180112+180-2x+168-2x = 180460-4x = 180-4x = 180-460-4x = -280x = -280/(-4)x = 70

valina [46]3 years ago

3 0

Answer: 70

=====================================

Explanation:

The exterior angles (2x+12) and (2x) have corresponding interior angles 180-(2x+12) and 180-(2x)

Triangle ABC has the following interior angles

A = 112

B = 180 - 2x

C = 180 - (2x+12) = 180-2x-12 = 168-2x

Add up the interior angles for A,B,C and set the result equal to 180. Solve for x

A+B+C = 180

(112)+(180-2x)+(168-2x) = 180

112+180-2x+168-2x = 180

460-4x = 180

-4x = 180-460

-4x = -280

x = -280/(-4)

x = 70

---------------

Side note:

2x = 2*70 = 140 is the exterior angle for B, so 180-140 = 40 is the interior angle for angle B

2x+12 = 2*70+12 = 152 is the exterior angle for C, so 180 - 152 = 28 is the interior angle for C

Add up the interior angles to find that A+B+C = 112+40+28 = 180, so this helps confirm we have the right x value.

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Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

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The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

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3 years ago

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Lunna [17]

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