If this is an IXL there should be a calculator for the lesson. This will help with your answer, if it doesn’t I’m sorry I couldn’t help.
Multiply first equaton by 2 and add to the other equation
6x+6y=12
<u>5x-6y=15 +</u>
11x+0y=27
11x=27
divide both sides by 11
x=27/11
sub back
3x+3y=6
divide both sides by 3
x+y=2
(27/11)+y=2
2 and 5/11+y=2
minus 2 and 5/11 both sides
y=-5/11
x=27/11
y=-5/11
(27/11,-5/11)
X+y+z≥627
x=222
y=194
222+194+z≥627
if we solved for z then
z≥221
3(-1) + 5y = 17
add 3 to both sides
5y=20
divide by 5
y=4
