Answer:
it was b!!!!!!!! i took the test
The statements that
apply are;
Say to the patient, "Step aside and I will get you
connected to the internet."
Ask the patient, "How were you feeling when you were
having this difficulty?"
Encourage the patient to recognize signs of mounting tension
and seek assistance.
Answer:
14 CO₂ will be released in the second turn of the cycle
Explanation:
<u>Complete question goes like this</u>, "<em>The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If acetyl-CoA is labeled with 14C at the carbonyl carbon, how many rounds of the cycle are required before 14CO2 is released?</em>"
<u>The answer to this is</u>;
- The labeled Acetyl of Acetyl-CoA becomes the terminal carbon (C4) of succinyl-CoA (which becomes succinate that is a symmetrical four carbon diprotic dicarboxylic acid from alpha-ketoglutarate).
- Succinate converts into fumarate. Fumarate converts into malate, and malate converts into oxaloacetate. Because succinate is symmetrical, the oxaloacetate can have the label at C1 or C4.
- When these condense with acetyl-CoA to begin the second round of the cycle, both of these carbons are discharged as CO2 during the isocitrate dehydrogenase and alpha-ketoglutarate dehydrogenase reactions (formation of alpha-ketoglutarate and succinyl-CoA respectively).
Hence, 14 CO₂ will be released in the second turn of the cycle.
Answer:
the salt is dissolved, resulting in a homogeneous solution.Explanation:
Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.
Answer:
B. cougar
Hope it helps! Ask me if you have doubts.
