Rewrite 8^1/3 using radical notation.

Mathematics

1 answer:

Aliun [14]3 years ago

4 0

The answer is cube root 8

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Perform the indicated operation.<br> h(n)=n-3<br> g(n)=-2n² + 2<br> Find (hºg)(n)

Anni [7]

Step-by-step explanation:

$h(n) = n - 3 \\ g(n) = - 2 {n}^{2} + 2 \\ \\ (h.g)(n) = h(n).g(n) \\ = (n - 3).( - 2 {n}^{2} + 2) \\ = n( - 2 {n}^{2} + 2) - 3( - 2 {n}^{2} + 2) \\ = - 2 {n}^{3} + 2n + 6{n}^{2} - 6 \\ \red{\boxed {\bold{\therefore \: (h.g)(n) = - 2 {n}^{3}+ 6{n}^{2} + 2n - 6}}}$

3 0

3 years ago

Xy=1 for x=2, dx/dt= -2 find dy/dt

dexar [7]

$\bf xy=1\iff y = \cfrac{1}{x}\iff y = x^{-1}\\\\
-----------------------------\\\\
\cfrac{dy}{dt}=-x^{-2}\cdot \cfrac{dx}{dt}\impliedby \textit{using the chain-rule}
\\\\\\
\left. \cfrac{dy}{dt}=-\cfrac{\frac{dx}{dt}}{x^2} \right|{
\begin{array}{llll}
x=2\\
\frac{dx}{dt}=-2
\end{array}}\implies \cfrac{dy}{dt}=-\cfrac{-2}{2^2}$