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laiz [17]
3 years ago
6

Write the equation of the line yhat is perpendicular to 5x+8y=16 and passes through (-5,7)

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

y-7=\frac{8}{5}(x+5)

or

y=\frac{8}{5} x +15

Step-by-step explanation:

To write the equation, convert the line to slope intercept form to find the slope.

5x+8y=16

8y=16-5x

y=-5/8 x +2

The slope of this line is -5/8. The slope of the line perpendicular to this line will be the negative reciprocal or 8/5.

Write the equation using the slope m=8/5 and the point slope form.

y-y_1=m(x-x_1)\\y-7=\frac{8}{5}(x--5)\\y-7=\frac{8}{5}(x+5)

This is the equation of the line. You can convert it to slope intercept form:

y-7=\frac{8}{5}(x+5)\\y-7 = \frac{8}{5}x + 8\\y=\frac{8}{5}x +15

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