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-Dominant- [34]
3 years ago
11

Find the area of a circle with radius, r = 57cm. Give your answer rounded to 3 SF

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

A≈10207.03cm²

Step-by-step explanation:

i think

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yesterday the temperature was 7 degrees fahrenheit . Today the temperature is 0 degrees fahrenheit . What was the change in the
lawyer [7]

Answer:

-7

Step-by-step explanation:

HOPE THIS HELPS

7 0
3 years ago
The volume of cube is 343 cubic centimeters.What is the suface area of the cube
Ann [662]
The cube root of 343 is 7.
One side has an area of 7*7 = 49 square cm
There are 6 sides to a cube
6 * 49 is the surface area = 294
7 0
3 years ago
The equation for a parabola has the form y = ax2 + bx + c, where a, b, and c are constants and a ≠ 0. find an equation for the p
sattari [20]
To solve the problem, substitute the given points for x in the given equation to get

-10=(-1)^2a+(-1)b+c\Rightarrow-10=a-b+c \\ -6=(1)^2a+(1)b+c\Rightarrow-6=a+b+c \\ -13=(2)^2a+(2)b+c\Rightarrow-13=4a+2b+c

Solving the three equations simultaneously, we have:

a = -3, b = 2 and c = -5

Therefore, the required equation is

y=-3x^2+2x-5
7 0
3 years ago
(6h+2)+(-7h-8) simplify?
lawyer [7]

Answer:

-h - 6

Step-by-step explanation:

(6h + 2) + (-7h - 8) <== remove parenthesis

6h + 2 - 7h - 8 <== combine like terms

6h - 7h + 2 - 8

-h - 6

Hope this helps!

4 0
2 years ago
8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.
PIT_PIT [208]

Answer:

a. 720

b. 0.3

Step-by-step explanation:

a.

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

b.

There are three cases that satisfy this condition

  1. first ball picked is 5, the others are not
  2. first ball is not 5, second is 5, third is not
  3. first and second ball is not five, third ball is 5

Each probabilities are:

  1. \frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}
  2. \frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}
  3. \frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}

Thus, one of the balls selected is the number 5 is then \frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}

5 0
3 years ago
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