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Alchen [17]
3 years ago
12

hot 'n spicy soup cost $2.39 a can brand x soup cost $1.39 a can wich cost more and what is the difference

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0
Hot 'n Spicy soup costs $1 more.
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Heather and Isabelle play a two-person game which is won by the first person to accumulate 10 points. At each turn Heather gains
Thepotemich [5.8K]
Heather winning, so the probability that Isabelle will win is : 1 whole right ? 

16/81 = 65 over 81
5 0
3 years ago
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Can you solve this equation 13m-22=9m-6
kati45 [8]


13m-22=9m-6

13m-9m-22=-6

4m-22=-6

4m=-6+22

4m=16

m=16/4

m=4


<em>Therefore, m is 4</em>

7 0
3 years ago
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An ice company charged $4.80 for 6 bags of ice. If a convenience store bought 2 bags of ice, how much would it have cost them?​
atroni [7]

Answer:

$1.60

Step-by-step explanation:

6/4.80 1/?

?= 0.8

by writing out the fractions and solving the proportion you will find that one bag costs $0.8. Multiply that by 2 and you get your answer which is $1.60

4 0
3 years ago
A teacher found that the mean number of pets, the students in her 5th grade class own, is 3 with a margin of error of 2.5. Const
Phoenix [80]
The margin of error is defined as
E=z^{*} \frac{\sigma}{ \sqrt{n} }
where
σ = population standard deviation
n = sample size
z* =  aconstant that depends on the confidence level. 
        At the 95% confidence level, z* = 1.96.

The confidence interval is calculated as
(μ - E, μ + E)

Given:
μ = 3, the mean number of pets,
E = 2.5, margin of error at the 95% confidence level.
Therefore the 95% confidence interval is
(3 - 2.5, 3 +2.5) = (0.5, 5.5)
Because we can only count whole numbers of pets, the confidence interval is (0, 5).

Answer:
At the 95% confidence level, the 5th graders own between 0  and 5 pets.  

7 0
4 years ago
On considère les deux expressions A et B. A=4(x+5)-8 B=x au carré+15. Avec x=1,puis avec x=3, je trouve le même résultat pour A
Ainat [17]

Explication étape par étape:

Compte tenu des expressions ';

A = 4 (x + 5) -8

B = x² + 15

Nous devons vérifier si A = B pour les deux valeurs de x à x = 1 et x = 3

à quand x = 1

A = 4 (1 + 5) -8

A = 4 (6) - 8

A = 24-8

A = 16

B = x² + 15

B = 1² + 15

B = 1 + 15

B = 16

Donc à quand x = 1, A = B = 16

quand x = 3

A = 4 (x + 5) -8

A = 4 (3 + 5) -8

A = 4 (8) - 8

A = 32-8

A = 24

B = 3² + 15

B = 9 + 15

B = 24

Également lorsque x = 3, A = B = 24

Cela montre que le postulat d'Emmas est juste.

5 0
3 years ago
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