Answer:
Step-by-step explanation:
-3 + 1/2n = 1/2 (-n + 14)
distribute
-3 + 1/2n = -1/2n + 7
-1/2n
cancel out -1/2n
-3 = n + 7
-10 = n
subtract 7
n = -10
Your answer would be 7y^(3)+32y^(2)+9
<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end.
In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
1. x=-3 y=4 2. x=5/2 y=15/2 3. x=9/5 y=-36/5 4. x=-2 y=1
