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natita [175]
2 years ago
11

Help please integral of sqrt (x^2+6x) dx

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
3 0
<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
 Because this is not an integration with specific bounds, you must include a constant at the end. In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
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Step-by-step explanation:

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Answer:

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