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natita [175]
3 years ago
11

Help please integral of sqrt (x^2+6x) dx

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
 Because this is not an integration with specific bounds, you must include a constant at the end. In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
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C (17,7) = (17!) / (7! *10!)

C (17,7) = (17*16*15*14*13*12*11*10!) / (7! *10!) then eliminate 10!

C (17,7) = (17*16*15*14*13*12*11) / (7*6*5*4*3*2*1) = (98017920)(5040)

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3 years ago
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il63 [147K]

Answer:

Step-by-step explanation:

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