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BaLLatris [955]
3 years ago
12

If an elephant could eat 2,500 pounds of food in 10 days how much can it eat in 1,000 days

Mathematics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

The elephant could eat 250,000 pounds of food in 1000 days

Step-by-step explanation:


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A pound of chocolate costs 6 dollars. Diane buys P pounds. Write an equation to represent the total cost c that Diane pays.
postnew [5]

Answer:

C=6P

Step-by-step explanation:

Because the cost (c) depends on the pounds (p), we have to multiple the weight by 6, because it is $6 per pound.

7 0
3 years ago
How do I find x?? It’s in french by the way.
DENIUS [597]

Answer:

The answer is 108

Step-by-step explanation:

The angle is obtuse and the only obtuse answer is 108.

5 0
3 years ago
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Jenny's chocolate bar is 34% cocoa. If the weight of the chocolate bar is 66 grams, how many grams of cocoa does it contain? Rou
damaskus [11]

Answer:

22.4 grams

Step-by-step explanation:

66 times 0.34 is 22.44

22.44 rounded to the nearest tenth is 22.4

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3 years ago
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Find the slope of the line that contains the two points (0,1) and (1,3)
klio [65]

Answer:

m=2 or y=2x+1

Step-by-step explanation:

first use the y2-y1/x2-x1 formula and then use y=mx+b formula

plug in 3 for y2 and 1 for y1

plug in 1 for x2 and 0 for x1

\frac{3-1}{1-0} =\frac{2}{1} =2

so ur slope is 2

_______________

for y=mx+b *extra info ig if u need it just incase*

i usually use the first point for this but u can use any one u want

plug in 0 for x

plug in 1 for y

and plug in 2 for m

1=2(0)+b

2*0=0

1=0+b

subtract o on both sides

1=b and b is ur y-intercept

y=2x+1

hope this helps

7 0
3 years ago
What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?
grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.  

1. Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{4};
  • 5\cdot 4=20=\overline{9};
  • 5\cdot 5=25=\overline{3};
  • 5\cdot 6=30=\overline{8};
  • 5\cdot 7=35=\overline{2};
  • 5\cdot 8=40=\overline{7};
  • 5\cdot 9=45=\overline{1};
  • 5\cdot 10=50=\overline{6}.

The multiplicative inverse of 5 in Z_{11} is 9.

2.   Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{3};
  • 5\cdot 4=20=\overline{8};
  • 5\cdot 5=25=\overline{1};
  • 5\cdot 6=30=\overline{6};
  • 5\cdot 7=35=\overline{11};
  • 5\cdot 8=40=\overline{4};
  • 5\cdot 9=45=\overline{9};
  • 5\cdot 10=50=\overline{2};
  • 5\cdot 11=55=\overline{7}.

The multiplicative inverse of 5 in Z_{12} is 5.

3.  Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{2};
  • 5\cdot 4=20=\overline{7};
  • 5\cdot 5=25=\overline{12};
  • 5\cdot 6=30=\overline{4};
  • 5\cdot 7=35=\overline{9};
  • 5\cdot 8=40=\overline{1};
  • 5\cdot 9=45=\overline{6};
  • 5\cdot 10=50=\overline{11};
  • 5\cdot 11=55=\overline{3};
  • 5\cdot 12=60=\overline{8}.

The multiplicative inverse of 5 in Z_{13} is 8.

8 0
4 years ago
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