All categories

3 years ago

Pls solve for x ASAP will give brainlist

Mathematics

1 answer:

kati45 [8]3 years ago

4 0

Answer:

121

Step-by-step explanation:

3x+4=7x

8x+4=12x

12+7 19

140°-19

You might be interested in

Anyone know how to solve this?

Dmitry_Shevchenko [17]

Answer:

whats the question..?

Step-by-step explanation:

7 0

3 years ago

Which of the following describes the transformation of p(x)=x3 to the function q(x)=−(x−6)3−4 ?

Anna71 [15]

Answer:

Step-by-step explanation:

(X) =x3 to the function q(x-6)3-4

5 0

2 years ago

Read 2 more answers

I really need help with this question

Mandarinka [93]

Just search up the name of your worksheet online and then at the end of the name/title,lesson and chapter/unit type in "answer key"

8 0

3 years ago

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

Translate to a system of equations:

omeli [17]

Answer:

m + n = 15

m - 3 = n

The numbers are 9 and 6

Step-by-step explanation:

From the question,

The sum of two numbers is fifteen; the first number is m and the second number is n. To translate to a system of equations, we can write that

m + n = 15 ..... (1)

Also, from the question,

One number is three less than the other,

Also, to translate to a system of equations, we can write that

m - 3 = n ...... (2)

If desired, we can determine m and n

From equation (1)

m + n = 15

Then,

m = 15 - n ...... (3)

Put the value of m in equation (3) into equation (2)

m - 3 = n

Then

15 - n - 3 = n

15 - 3 = n + n

12 = 2n

n = 12/2

∴ n = 6

For m, put the value of n into equation 3

m = 15 - n

m = 15 - 6

m = 9

∴ m = 9 and n = 6

Hence, the numbers are 9 and 6

3 0

3 years ago