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Veronika [31]
3 years ago
10

How do you solve this? its area

Mathematics
1 answer:
Softa [21]3 years ago
7 0
You times height and width and area than get your answer
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Ruby weighs 88 lbs. Her weight is 12 lbs. less than half her mother's weight. How much does her mother weigh?
GenaCL600 [577]

88 = m - 12

<u>+ 12       + 12</u>

100 = m

8 0
3 years ago
Read 2 more answers
Find the area of the circle with a circumference of
Anton [14]

Answer:

706.50 mm^2

Step-by-step explanation:

The formula to find the circumference is 2πr (r : radius)

if the circumference is 30π the the radius is = 15

to find the area we use the following formula :

π*r^2

r = 15 and π is given as 3.14

(3.14)*15^2 = 706.50 mm^2

8 0
3 years ago
A 100 foot ladder is leaning against a tree so that the top of the ladder is 96 feet above the ground. How far is the base of th
ahrayia [7]

Answer:The base of the ladder from the tree is 28ft

Step-by-step explanation:

Using pythagorean theorem

Let 100ft= hypothesis is the right angle triangle

Let 96ft be the height of the ladder

Let x be the base of the right angle triangle between the base of the ladder and the tree

h^2=a^2+b^2

100^2=96^2 +b^2

10,000=9216 +b^2

b^2=10,000-9216

b=sqrt(784)

b=28ft

8 0
4 years ago
Read 2 more answers
What is 1/3 + 1/6 equal
tatuchka [14]

Answer: 1/2

Step-by-step explanation: 1/3 + 1/6

1- multiply 1/3 by 2

2- 2/3 + 1/6= 3/6

3- reduce to 1/2

hope this helps pls mark me brainliest

7 0
3 years ago
You travel 5 miles downstream in a kayak at a speed of r miles per hour. You turn around and travel 6 miles upstream at a speed
Vlad1618 [11]
Kyle, d = rt, right? This means that t = d/r. If we call the rate of the current c, then her rate upstream is hindered by the current and is 3 - c. Downstream is 3 + c. The total time is 6 hours... 5/(3 - c) + 5/(3 + c) = 6 Once we put everything over the same denominator, we don't need it anymore. 5(3 + c) + 5(3 - c) = 6(3 - c)(3 + c) 15 + 5c + 15 - 5c = 54 - 6c2
30 = 54 - 6c26c2 = 24c2 = 4c = 2 2 mph 
3 0
3 years ago
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