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2 years ago

Acme has these paper towels on sale, 8 rolls for $5.99.

Mathematics

1 answer:

forsale [732]2 years ago

8 0

Answer:

The ratio would be 8:5.99 or 8/5.99

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On one day a Plumber Joe earned $80 on a plumbing job. Out of his earnings he spent $6.85 on tea and snacks, $5.50 on food and $

In-s [12.5K]

Answer:

Joe saved 68.25

Step-by-step explanation:

Subtract 6.85 from 80, you get 73.15

Subtract 5.50 from 73.15 and you get 67.65.

Subtract 21.40 from 67.65 and you get 46.25.

Add 22 to that amount, you get 68.25.

P.S

Have an Amazing Day! I Hope this Helps and Good Luck!!

~Faker/Tosrel

4 0

2 years ago

What is the true solution to the equation below?

Marina CMI [18]

Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

$\ln \left(e^{\ln \left(x\right)}\right)+\ln \left(e^{\ln \left(x\right)\cdot \:2}\right)=2\ln \left(8\right)$

$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

$\ln \left(x\right)+\ln \left(x\right)\cdot \:2=2\ln \left(8\right)$

$\mathrm{Add\:similar\:elements:}\:\ln \left(x\right)+2\ln \left(x\right)=3\ln \left(x\right)$

$3\ln \left(x\right)=2\ln \left(8\right)$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3\ln \left(x\right)}{3}=\frac{2\ln \left(8\right)}{3}$

$\ln \left(x\right)=\frac{2\ln \left(8\right)}{3}.....A$

Solving the right side of the equation A.

$\frac{2\ln \left(8\right)}{3}$

$\ln \left(8\right):\quad 3\ln \left(2\right)$

Because

$\ln \left(8\right)$

$\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3$

⇒ $\ln \left(2^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(2^3\right)=3\ln \left(2\right)$

$\frac{2\ln \left(8\right)}{3}=\frac{2\cdot \:3\ln \left(2\right)}{3}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6$

$=\frac{6\ln \left(2\right)}{3}$

$\mathrm{Divide\:the\:numbers:}\:\frac{6}{3}=2$

$=2\ln \left(2\right)$

So, equation A becomes

$\ln \left(x\right)=2\ln \left(2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$=\ln \left(2^2\right)$

$=\ln \left(4\right)$

$\ln \left(x\right)=\ln \left(4\right)$

$\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)$

$x=4$

Therefore, the solution is

$x=4$

6 0

2 years ago

Read 2 more answers

¿A cuál ecuación corresponde la expresión x=3?

Bas_tet [7]

Answer:

(8x − 2x ) + (−x − 2) = (5x − 3) − (4 −x ) a) Ecuación de Primer Grado. b)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Table of value y = -4x - 12

Scorpion4ik [409]

X Y
————-
-2. -4
-1. -8
0. -12
1. -16
2. -20

8 0

2 years ago

Neal opened a savings account 11 years ago with a deposit of $2,335.69. The account has an interest rate of 4.3% compounded dail

Vinvika [58]

Answer: $1,412.52

Step-by-step explanation:

Formula to calculate the accumulated amount if P principal invested for t years at a rate of interest r that compounded daily is given by:-

$A=P(1+\dfrac{r}{365})^{365t}$

Given: P= $2,335.69

r= 4.3%= 0.043

t= 11 years

Then,

$A=2335.69(1+\dfrac{0.043}{365})^{365\times11}\\\\=2335.69(1+0.000117808219178)^{4015}\\\\=2335.69(1.000117808219178)^{4015}\\\\= 2335.69(1.6047566747)\\\\=3748.09044309\approx3748.21\\\\\Rightarrow\ A=\$3748.21$

Interest earned = A-P

= $3748.21- 2335.69.

= $1412.52

Hence, Neal earned $1,412.52 as interest.

8 0

2 years ago