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marysya [2.9K]
3 years ago
10

How do you determine if the graph opens up or opens down?

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

There is an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

Step-by-step explanation

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How are independent and dependent variables different
alisha [4.7K]

Answer:

Step-by-step explanation:

The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

6 0
3 years ago
40 POINTS <br><br> please answer me this question with an explanation
user100 [1]

Answer:

(16/3,-4)

Step-by-step explanation:

  1. y=-3/4x & y=3/2x -12
  2. then solve for x which means -3/4x=3/2x-12
  3. then the value of x=16/3
  4. put the x value in one equation
  5. y=3/4(16/3)
  6. then the value of y=-4
4 0
2 years ago
Read 2 more answers
What is the quadratic regression equation that fits these data?
ruslelena [56]

Answer:

Step-by-step explanation:

The answer is D. Use the Stat and then Edit button on your TI calculator to edit the values in L1 and L2 tables. In L1 enter 0, 1, 2, 3, 4, 5 and then arrow over and enter the y values into L2 the same way. Enter the number 12, then hit enter; enter the number 14, hit enter; enter the number 15 and then hit enter, etc. Do the same for the values that are going into L1.

When that is done, hit the Stat button again and arrow down to QuadReg and hit enter. Depending upon your calculator, you may have to arrow down to "calculate" or the calculator may display the equation immediately after hitting QuadReg. Again, it all depends upon your calculator.

5 0
3 years ago
Read 2 more answers
The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option
postnew [5]

Answer:

The equations that represent the reflected function are

f(x)=5(\frac{1}{5})^{-x}

f(x)=5(5)^{x}

Step-by-step explanation:

The correct question in the attached figure

we have the function

f(x)=5(\frac{1}{5})^{x}

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

f(−x) = f(x).

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative  x-values)

f(x)=5(\frac{1}{5})^{-x}

An equivalent form will be

f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}

therefore

The equations that represent the reflected function are

f(x)=5(\frac{1}{5})^{-x}

f(x)=5(5)^{x}

9 0
3 years ago
Read 2 more answers
What is the slope intercept form of y= -2
Mashcka [7]

The slope-intercept form: y = mx + b

(m - slope, b - y-intercept)

We have y = -2. It's the slope intercept form where m = 0 and b = -2.

y = -2 → y = 0x - 2

8 0
3 years ago
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