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3 years ago

Please help me with this how to find y.

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer:

90 degrees

Step-by-step explanation:

Anton [14]3 years ago

4 0

I’m not sure but it will most likely be 90 degrees!

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Mya had 12 assignments to complete by Friday of this week. So far, she completed 75% percent of her assignments this week. How m

lesya692 [45]

Answer:

3 assignments incomplete.

Step-by-step explanation:

context: 75% can be rewritten as 0.75

12 × 0.75 = 9 assignments completed.

The above equation shows the amount of assignments that have been already completed. In order to find out how many assignments she has yet to have completed, we need to subtract these amounts.

12 - 9 = 3 assignments incomplete.

5 0

3 years ago

Please help me with this question

inn [45]

Answer:

C. 13, 26, 39

Step-by-step explanation:

13 is a prime number so the numbers must be 13 and 1. Thus, you are just listing the first multiples of 13.

7 0

3 years ago

Read 2 more answers

0.4 times by 3.7<br>multiplying by decimals

fomenos

3.7
x. .4
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then use the same number of decimals as are in the first two numbers added together. both have 1 so we need two decimals

1.48

6 0

4 years ago

Read 2 more answers

Solve. Good luck! Please do not try to google this.

Elena L [17]

$\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}$
$\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}$
$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

4 years ago

1. A rectangular tile has a decorative

Akimi4 [234]

Answer:

216

Step-by-step explanation:

Each of the 36 tiles has 3×2 = 6 triangles, so there are a total of ...

36×6 = 216 . . . triangles

6 0

4 years ago