I think it’s -36, not 100% sure though
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
y = 4x + 3
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first step in solving the equation is to cube both sides:
(∛x)³ = (-4)³ . . . . . = (-4)(-4)(-4) = 16(-4) = -64
x = -64 . . . . . simplified
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We're not sure what "checking" is supposed to involve here. Usually, one would check the answer by seeing if a true statement is made when the answer is put into the original equation.
∛(-64) = -4 . . . true
Many calculators will not compute √(-64) because they compute roots using logarithms. The log of a negative number is not defined.
So, the way one would check this is to cube both sides, which is how we got the answer in the first place. We expect the same result from doing the same operation again, so it isn't really a check.
Answer:
A/15=5
so multiply 15*5
you would get 75
therefore a=75
Step-by-step explanation: