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vesna_86 [32]
3 years ago
13

According to this diagram, what is tan 74

Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0

Answer: F-24/7

Step-by-step explanation: sahcohtoa

tan is opposite over adjacent so 24/7

mariarad [96]3 years ago
7 0

Answer:

\boxed{F.\:\:\frac{24}{7} }

Step-by-step explanation:

The tangent ratio is the ratio of the length of the opposite side to the length of the adjacent side.

This implies that;

\tan(74\degree)=\frac{Opposite}{Adjacent}

The length of the side opposite to the 74 degree angle is 24 units.

The length of the side adjacent to the 74 degree angle is 7 units.

We substitute these values into the formula to obtain;

\tan(74\degree)=\frac{24}{7}

The correct answer is option F

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Let the function f be defined as f(x)= 5x^2 - 7(4x+3). What is the value of f(3)
Katen [24]

Answer:

f(x) = -60 is your answer

Step-by-step explanation:

Plug in 3 for x

f(x) = 5x² - 7(4x + 3)

f(x) = 5(3²) - 7(4(3) + 3)

Follow PEMDAS. First, solve the parenthesis

3² = 9

4(3) + 3 = 12 + 3 = 15

f(x) = 5(9) - 7(15)

Multiply

f(x) = 45 - 105

Simplify. Subtract

f(x) = 45 - 105

f(x) = -60

f(x) = -60 is your answer

~

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Answer:

$161.34

Step-by-step explanation:

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Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

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= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

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What is the equation in point slope form of the line that is parallel to the given line and passes through the point (4,1)?
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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

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so we're really looking for the equation of a line with a slope of 2 and that it passes through (4 , 1)

(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{2}(x-\stackrel{x_1}{4})

kinda twins.

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