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3 years ago

Use slope to determine if lines PQ and RS are parallel,

Mathematics

1 answer:

liubo4ka [24]3 years ago

8 0

Answer:

PQ and RS are parallel to each other

Step-by-step explanation:

Slope of two points (x1,y1) and (x2,y2) is given by

slope = (y2-y1)/(x2-x1)

for two lines to be parallel slope should be equal
for two lines to be perpendicular product of slope should be -1
_______________________________________________

Lets find the slope of PQ and RS

for PQ P(2, -1), Q(-3,-1), R(-11, 9), S(-7, 9)

slope PQ = (-1 -(-1))/(-3 -2) = (-1 + 1)/5 = 0/5 = 0

Slope RS = (9-9)/(-7 - (-11) ) = 0/4 = 0

Since

slope PQ = slope RS = 0

Hence PQ and RS are parallel to each other

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Answer:

Step-by-step explanation:

This is not nearly as threatening and scary as I first thought it was. You must be in the section in Geometry where you are taught that perimeter of similar figures exist in a one-to-one relationship while areas of similar figures exist in a squared-to-squared relationship. We will use that here.

The area formula for a regular polygon is

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We are given that the area of the triangle inside that polygon is 22.022 units squared. Knowing that the area formula for a triangle is

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It just so happens that the height of that triangle is also the apothem of the polygon, so now we have what we need to find the area of the polygon:

$A=\frac{1}{2}(5.5055)(40)$

which gives us an area of

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Here is where we can use what we know about similar figures and the relationships between perimeters and areas. We will set up a proportion with the smaller polygon info on top and the larger info on bottom. We know that the larger is 3 times the smaller, so the ratio of smaller to larger is

$\frac{s}{l}:\frac{1}{3}$

Since perimeter is one-to-one and we know the perimeter of the smaller, we can create a proportion to solve for the perimeter of the larger:

$\frac{s}{l}:\frac{1}{3}=\frac{40}{x}$

Cross multiply to get that the perimeter is 120 units. You could also have done this by knowing that if the larger is 3 times the size of the smaller, then the side measure of the larger is 24, and 24 * 5 = 120. But we used the way we used because now we have a means to find the area of the larger since we know the area of the smaller.

Area exists in a squared-to-squared relationship of the perimeter which is one-to-one. If the perimeter ratio is 1:3, then the area relationship is

$\frac{s}{l}:\frac{1^2}{3^2}$ which is, simplified:

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Since we know the area for the smaller, we can sub it into a proportion and cross multiply to solve for the area of the larger.

$\frac{s}{l} :\frac{1}{9} =\frac{110.11}{x}$

A of the larger is 990.99 units squared

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3 years ago