Ask question

Ask question

All categories

2 years ago

5

How do you simplify (9x^8y^3)^1/2

1 answer:

jekas [21]2 years ago

7 0

I hope this helps you

You might be interested in

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

2 years ago

Andre drew a plan of the courtyard at a scale of 1 to 60 on his drawing one side of the courtyard is 2.75 inches what is the act

Furkat [3]

Answer:

165 inches

Step-by-step explanation:

The scale is 1 to 60, so real measurements are 60 times bigger than drawing measurements.

2.75 inches * 60 = 165 inches

5 0

2 years ago

Read 2 more answers

Find the circumference of the circle.

Softa [21]

Answer:

2pie R so it would be 15.7

3 0

2 years ago

The perimeter of a square is 36<br>what is the area of the square?

zmey [24]

Answer: 81 units²

Step-by-step explanation: To solve this problem, remember that the formula for the area of a square is 4s.

Therefore, since the perimeter of the given square is 36, we have 36 = 4s and dividing both sides by 4, 9 = s.

Now, remember that the formula for the area of a square is s² and since the length of a side of the given square is 9, we have (9)² or 81.

So the area of a square that has a perimeter of 36 is 81 units².

6 0

2 years ago

A scientist is studying the population growth rates of two different species of rats in the same laboratory conditions. The popu

Korolek [52]

Since, population of species A is represented by : $P=2^{x} +19$

Let us find the population of species A, at the end of week 1:

i.e., x = 1

i.e., $P(1)=2^{1} +19$

i.e., $P(1)=2 +19$

i.e., $P(1)=21$

Also, since population of species B is represented by : $P=3^{x} +18$

Let us find the population of species B, at the end of week 1:

i.e., x = 1

i.e., $P(1)=3^{1} +18$

i.e., $P(1)=3 +18$

i.e., $P(1)=21$

Thus, at the end of 1 week, species A and species B will have the same population.

Hence, option D is correct.

4 0

2 years ago