3 years ago

How do you simplify (9x^8y^3)^1/2

Mathematics

1 answer:

jekas [21]3 years ago

7 0

I hope this helps you

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Answer:

95% Confidence interval: (31.32%,47.04%)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 148

Number of people who sleep for 8 hours or longer, x = 58

$\hat{p} = \dfrac{x}{n} = \dfrac{58}{148} = 0.3918$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting the values, we get:

$0.3918\pm 1.96(\sqrt{\dfrac{0.3918(1-0.3918)}{148}})\\\\ = 0.3918\pm 0.0786\\\\=(0.3132,0.4704)=(31.32\%,47.04\%)$

(31.32%,47.04%) is the required 95% confidence interval.

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3 years ago

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