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vazorg [7]
3 years ago
5

How do you simplify (9x^8y^3)^1/2

Mathematics
1 answer:
jekas [21]3 years ago
7 0
I hope this helps you

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Pls help!!!! i have eight more minutes to answer<br> eeeeeeeeee
Sati [7]
Answer: B) 16 units

Step-by-Step Explanation:

As we can observe from the graph,

Length (l) = 5 units
Breadth (b) = 3 units

Perimeter = 2(l + b)

Therefore,
= 2(l + b)
= 2(5 + 3)
= 2(8)
= 2 * 8
=> 16

Perimeter = 16 units
6 0
2 years ago
HELP ASAP 10 POINTSSSS
lord [1]

Use the Pythagorean theorem   (a^2 + b^2 = c^2)

7^2 + 24^2 = x^2

x^2 = 625

x = 25

6 0
2 years ago
14 1/6 - 7 1/3 in simplest form <br> Help plz
Firdavs [7]

Answer: 7 -1/6

Step-by-step explanation:

Multiply the denominator and numerator (1/3) by 2 to get 2/6, then do 1/6-2/6, which gives you a negative. Then subtract your whole numbers (14-7) to get 7 -1/6

7 0
3 years ago
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Svetradugi [14.3K]
59/12 if you want to simplify more 4 11/12
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2 years ago
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A plane flew 720 mi with a steady 30 mi/h tailwind. The pilot then returned to the starting point, flying against that same wind
NNADVOKAT [17]

Answer:

Plane's speed is 150 miles/hour

Step-by-step explanation:

Let the plane's airspeed be x

Speed of wind is 30 miles/hour

When a plane flew with the wind , Speed = (x+30)

So, the speed plain with wind on going = (x+30)

Since we are given that on returning plane fly against the wind .

So,When a plane flew against the wind , Speed = (x-30)

So, the speed plain against wind on returning = (x-30)

Distance = 720 miles .

Time = \frac{Distance}{Speed}

So, time on going  =\frac{720}{(x+30)}

Time on returning  =\frac{720}{(x-30)}

Now we are given that the total time for the whole trip (going + returning) = 10 hours.

So,  \frac{720}{(x+30)}+\frac{720}{(x-30)}=10

\frac{720x-21600+720x+21600}{(x+30)(x-30)}=10

720x-21600+720x+21600=10(x+30)(x-30)

720x+720x=10(x+30)(x-30)

1440x=10(x^2 -[30]^2)

144x=x^2 -900

x^2-144x -900=0

x^2-150x+6x -900=0

x(x-150)+6(x -150)=0

(x-150)(x+6)=0

x= 150,x= -6

So, the plane's speed is 150 miles/hour

4 0
3 years ago
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