I need help for a major grade quiz !!

Mathematics

1 answer:

arsen [322]3 years ago

5 0

Answer: The answer would be D.

Step-by-step explanation: I put down the points then simply reflected it over the y-axis. I did this by using the the opposite of the x number and the same y number. Hope this helps!

You might be interested in

Look at this prism and its net. Rectangular prism with length labeled 5 meters, width labeled 7 meters, and height labeled 12 me

kaheart [24]

There will be three pairs of matching sides: one pair 5x7, one pair 5x12 and one pair 12x7. We can compute the are of each side (in pairs) and then add up the total:

$A_{surf}=2\times(l \times w)+2\times(l \times h)+2\times(h \times w)$
$A_{surf}=2\times(5\times7)+2\times(5\times12)+2\times(12\times7)$
$A_{surf}=2\times35+2\times60+2\times84$
$A_{surf}=70+120+168$
$A_{surf}=358$
$A_{surf}=358m^{2}$

5 0

3 years ago

kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that $n = 300$

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied. So we use $p = 0.93$