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gladu [14]
2 years ago
8

the volume of a pyramid whose base is aright triangle is 234 units. If the two legs of the right triangle measures 9 units and 1

2 units find the height of the pyramid.
Mathematics
1 answer:
Kobotan [32]2 years ago
7 0

If the volume of this pyramid is 234 units, the height of the pyramid is equal to 13 units.

<h3>How to calculate the volume of a pyramid.</h3>

Mathematically, the volume of a pyramid is given by the formula:

Volume = \frac{1}{3} \times base\;area \times height

<u>For the </u><u>base area</u><u>:</u>

The area of a right triangle is given by:

A=\frac{ab}{2} \\\\A=\frac{9 \times 12}{2} \\\\A=\frac{108}{2}

A = 54 square units.

<u>Given the following data:</u>

Volume of a pyramid = 234 units.

Side lengths of right triangle = 9 and 12 units.

Now, we can calculate the height of the pyramid:

234 = \frac{1}{3} \times 54 \times height\\\\234=18h\\\\h=\frac{234}{18}

h = 13 units.

Read more on pyramid here: brainly.com/question/16315790

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To answer this, we will need to know:

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First, we will need to find the slope of this equation. To find this, we must simplify the equation 3x+5y=38 into y=mx+b form. Lets do it!

3x+5y=38
= 5y = -3x+38 (Subtract 3x from both sides)
= y= -\frac{3}{5}x+ \frac{38}{5} (Divide both sides by 5) 

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is \frac{5}{3}. 

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

\frac{y-y _{1} }{x- x_{1} }=m

Substituting values, we find that:

\frac{y-4}{x-6}= \frac{5}{3}

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that: 

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Thank you, and I wish you luck.
8 0
4 years ago
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Answer:

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Step bu step:

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3 years ago
Can anyone help me? If f (x) = -2x +5, what is f (-3x) equal to?
LekaFEV [45]

Answer:

B

Step-by-step explanation:

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substitute x with -3x

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3 years ago
If lim x-&gt; infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

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as required.

3 0
3 years ago
It’s elimination <br> -x+6y=3<br> -4x-2y=-14
gavmur [86]

Answer:

(3,1)

Step-by-step explanation:

Multiplying the second equation by 3, we get

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Now, adding this to the first equation, we get

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Therefore, x=3

plugging in x=3 to the first equation, we get that

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adding 3 to both sides,

6y=6

therefore, y=1

6 0
3 years ago
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