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natita [175]
3 years ago
9

3/7 x 4/5 = what in lowest terms?

Mathematics
2 answers:
s2008m [1.1K]3 years ago
5 0
3/7 x 4/5 = 12/35 in lowest terms.
iren [92.7K]3 years ago
5 0
3 x 4 = 12
7 x 5 = 35
Answer: 12/35
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POSSIBLE POINTS. 1
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Answer:

Step-by-step explanation:

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1 year ago
The math team went to lunch to celebrate Ms. Renft's birthday on February 11th. The
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3 years ago
What is the equation of the circle graphed below? Use the caret ( ^ ) to enter any exponents; for example, write x2 as x^2.
kvv77 [185]
Equation of a circle in standard form:
(x-h)²+(y-k)²=r²
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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
How do you simplify sin^4-cos^4=2sin^2-1?
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\bf \textit{Double Angle Identities} \\\\ cos(2\theta)= \begin{cases} cos^2(\theta)-sin^2(\theta)\\ 1-2sin^2(\theta)\\ 2cos^2(\theta)-1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{array}{llll} sin^4(\theta )-cos^4(\theta )&=&2sin^2(\theta )-1\\[1em] [sin(\theta )]^4-[cos(\theta )]^4&=&-[1-2sin^2(\theta )]\\[1em] \stackrel{\textit{difference of squares}}{[[sin(\theta )]^2]^2-[[cos(\theta )]^2]^2}&=&-[cos^2(\theta )-sin^2(\theta )]\\[1em] [sin^2(\theta )-cos^2(\theta )][sin^2(\theta )+cos^2(\theta )]&=&sin^2(\theta )-cos^2(\theta )\\[1em] [sin^2(\theta )-cos^2(\theta )][1]&=\\\\ sin^2(\theta )-cos^2(\theta ) &=\end{array}

8 0
3 years ago
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